이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define ld long double
#define pb push_back
#define fi first
#define se second
#define en '\n'
#define sp ' '
#define tb '\t'
#define ri(n) int n; cin >> n
#define rl(n) ll n; cin >> n
#define rs(s) string s; cin >> s
#define rc(c) char c; cin >> c
#define rv(v) for (auto &x : v) cin >> x
#define pven(v) for (auto x : v) cout << x << en
#define pv(v) for (auto x : v) cout << x << sp; cout << en
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define yes cout << "YES" << en
#define no cout << "NO" << en
#define smin(a, b) a = min(a, b)
#define smax(a, b) a = max(a, b)
#define ssort(a, b) if (a < b) swap(a, b)
#define bitcnt(a) (__builtin_popcountll(a))
#define bithigh(a) (63-__builtin_clzll(a))
#define lg bithigh
#define highpow(a) (1LL << (ll)lg(a))
using namespace std;
class segtree{
int n;
vector<int> tree;
int update(int s, int l, int r, int pos, int x){
if (l > pos || r < pos) return tree[s];
if (l == r) return tree[s] = x;
int m = (l + r)>>1;
int a = update(2*s, l, m, pos, x);
int b = update(2*s+1, m+1, r, pos, x);
return tree[s] = max(a, b);
}
int query(int s, int l, int r, int ql, int qr) const {
if (l > qr || r < ql) return 0;
if (l >= ql && r <= qr) return tree[s];
int m = (l + r)>>1;
int a = query(2*s, l, m, ql, qr);
int b = query(2*s+1, m+1, r, ql, qr);
return max(a, b);
}
public:
void Assign(int s){
n = highpow(s);
if (bitcnt(s) > 1) n <<= 1;
tree.assign(2*n, 0);
}
void update(int pos, int x){ update(1, 0, n-1, pos, x); }
int query(int l, int r) const { return query(1, 0, n-1, l, r); }
};
const ll LINF = 4e18;
const int mxN = 1e6+10, INF = 2e9;
ll n, m, r[mxN], dp[mxN];
array<ll, 2> a[mxN];
segtree st;
void Solve(){
cin >> n >> m;
set<int> s;
for (int i = 0; i < n; i++){
cin >> a[i][0]; a[i][1] = -i;
if (i >= m-1) s.insert(i);
}
sort(a, a+n);
for (int i = 0; i < n; i++){
int j = -a[i][1];
vector<int> v;
for (auto it = s.lower_bound(j); it != s.end() && *it < j+m; it++)
v.pb(*it);
for (int t : v) s.erase(t);
auto it = s.lower_bound(j);
if (it == s.end()) r[j] = n-1;
else r[j] = *it;
}
reverse(a, a+n);
st.Assign(n);
int ans = 0;
for (int i = 0; i < n; i++){
int j = -a[i][1];
int cur = st.query(j, r[j])+1;
smax(ans, cur);
st.update(j, cur);
}
cout << ans << en;
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0); cerr.tie(0);
cout << setprecision(12) << fixed;
cerr << setprecision(12) << fixed;
cerr << "Started!" << endl;
int t = 1;
//cin >> t;
while (t--)
Solve();
return 0;
}
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