이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*input
5 2
4 10
4 5
1 2
2 3
3 6
*/
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
using namespace __gnu_pbds;
typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<ll,ll>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#define GET(v,x) lower_bound(ALL(v),x)-v.begin()
const int maxn=2e5+5;
const ll INF=0x3f3f3f3f;
const ld PI=acos(-1.0l);
const ld eps=1e-6;
const ll INF64=4e18+1;
const int MOD=1e9+7;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
out<<P.f<<' '<<P.s;
return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?"\n":"");
return out;
}
inline ll mult(ll a,ll b){
return a*b%MOD;
}
ll mypow(ll a,ll b){
if(b<=0) return 1;
ll res=1LL;
while(b){
if(b&1) res=mult(res,a);
a=mult(a,a);
b>>=1;
}
return res;
}
int l[maxn],r[maxn];
int suff[maxn];
int mn[maxn][20];
int get(int l,int r){
int ans=0;
for(int j=19;j>=0;j--){
if(mn[l][j]<=r){
l=mn[l][j];
ans+=(1<<j);
}
}
return ans;
}
int main(){
ios::sync_with_stdio(false),cin.tie(0);
int n,k;
cin>>n>>k;
vector<pii> v;
vector<int> dsc;
REP(i,n){
cin>>l[i]>>r[i];
//--r[i];
dsc.pb(l[i]),dsc.pb(r[i]);
}
SORT_UNIQUE(dsc);
REP(i,2*n) suff[i]=INF;
REP(i,n){
l[i]=GET(dsc,l[i]),r[i]=GET(dsc,r[i]);
MNTO(suff[l[i]],r[i]);
}
for(int i=2*n-2;i>=0;i--) MNTO(suff[i],suff[i+1]);
REP(i,2*n){
//cout<<suff[i]<<' ';
mn[i][0]=suff[i];
}
REP1(j,19){
REP(i,2*n){
if(mn[i][j-1]<INF) mn[i][j]=mn[mn[i][j-1]][j-1];
else mn[i][j]=INF;
//cout<<i<<' '<<j<<' '<<mn[i][j]<<'\n';
}
}
set<pii> s;
s.insert({0,0}),s.insert({2*n-1,2*n-1});
vector<int> ans;
int tot=get(0,2*n-1);
if(tot<k){
cout<<-1;
return 0;
}
REP(i,n){
auto it=s.lower_bound({l[i],r[i]});
if((it!=s.begin() and (*prev(it)).s>l[i]) or (it!=s.end() and ((*it).f)<r[i])){
continue;
}
if(tot-get((*prev(it)).s,(*it).f)+1+get((*prev(it)).s,l[i])+get(r[i],(*it).f)>=k){
s.insert({l[i],r[i]});
ans.pb(i+1);
}
if(sz(ans)==k) break;
}
if(sz(ans)!=k) cout<<-1;
else cout<<ans;
}
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