제출 #659186

#제출 시각아이디문제언어결과실행 시간메모리
659186zaneyuEvent Hopping 2 (JOI21_event2)C++14
1 / 100
136 ms27336 KiB
/*input 5 2 4 10 4 5 1 2 2 3 3 6 */ #include<bits/stdc++.h> using namespace std; #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> //#pragma GCC optimize("O3,unroll-loops") //#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") using namespace __gnu_pbds; typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set; //order_of_key #of elements less than x // find_by_order kth element using ll=long long; using ld=long double; using pii=pair<ll,ll>; #define f first #define s second #define pb push_back #define REP(i,n) for(int i=0;i<n;i++) #define REP1(i,n) for(int i=1;i<=n;i++) #define FILL(n,x) memset(n,x,sizeof(n)) #define ALL(_a) _a.begin(),_a.end() #define sz(x) (int)x.size() #define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end())))) #define GET(v,x) lower_bound(ALL(v),x)-v.begin() const int maxn=2e5+5; const ll INF=0x3f3f3f3f; const ld PI=acos(-1.0l); const ld eps=1e-6; const ll INF64=4e18+1; const int MOD=1e9+7; #define lowb(x) x&(-x) #define MNTO(x,y) x=min(x,(__typeof__(x))y) #define MXTO(x,y) x=max(x,(__typeof__(x))y) template<typename T1,typename T2> ostream& operator<<(ostream& out,pair<T1,T2> P){ out<<P.f<<' '<<P.s; return out; } template<typename T> ostream& operator<<(ostream& out,vector<T> V){ REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?"\n":""); return out; } inline ll mult(ll a,ll b){ return a*b%MOD; } ll mypow(ll a,ll b){ if(b<=0) return 1; ll res=1LL; while(b){ if(b&1) res=mult(res,a); a=mult(a,a); b>>=1; } return res; } int l[maxn],r[maxn]; int suff[maxn]; int mn[maxn][20]; int get(int l,int r){ int ans=0; for(int j=19;j>=0;j--){ if(mn[l][j]<=r){ l=mn[l][j]; ans+=(1<<j); } } return ans; } int main(){ ios::sync_with_stdio(false),cin.tie(0); int n,k; cin>>n>>k; vector<pii> v; vector<int> dsc; REP(i,n){ cin>>l[i]>>r[i]; //--r[i]; dsc.pb(l[i]),dsc.pb(r[i]); } SORT_UNIQUE(dsc); REP(i,2*n) suff[i]=INF; REP(i,n){ l[i]=GET(dsc,l[i]),r[i]=GET(dsc,r[i]); MNTO(suff[l[i]],r[i]); } for(int i=2*n-2;i>=0;i--) MNTO(suff[i],suff[i+1]); REP(i,2*n){ //cout<<suff[i]<<' '; mn[i][0]=suff[i]; } REP1(j,19){ REP(i,2*n){ if(mn[i][j-1]<INF) mn[i][j]=mn[mn[i][j-1]][j-1]; else mn[i][j]=INF; //cout<<i<<' '<<j<<' '<<mn[i][j]<<'\n'; } } set<pii> s; s.insert({0,0}),s.insert({2*n-1,2*n-1}); vector<int> ans; int tot=get(0,2*n-1); if(tot<k){ cout<<-1; return 0; } REP(i,n){ auto it=s.lower_bound({l[i],r[i]}); if((it!=s.begin() and (*prev(it)).s>l[i]) or (it!=s.end() and ((*it).f)<r[i])){ continue; } if(tot-get((*prev(it)).s,(*it).f)+1+get((*prev(it)).s,l[i])+get(r[i],(*it).f)>=k){ s.insert({l[i],r[i]}); ans.pb(i+1); } if(sz(ans)==k) break; } if(sz(ans)!=k) cout<<-1; else cout<<ans; }
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