제출 #658006

#제출 시각아이디문제언어결과실행 시간메모리
658006LoboA Difficult(y) Choice (BOI21_books)C++17
100 / 100
1 ms340 KiB
#include <bits/stdc++.h>
#include "books.h"
using namespace std;
#define int long long
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
#define all(x) x.begin(),x.end()
const int maxn = 1e5+10;
const int maxv = 2e18+10;
int n, b[maxn];
int cnt;
int qry(int32_t i) {
    if(b[i] == 0) {
        assert(cnt--);
        return b[i] = skim(i);
    }
    return b[i];
}

int qrysum(int l, int r) {
    int sum = 0;
    for(int i = l; i <= r; i++) {
        sum+= qry(i);
        sum = min(sum,maxv);
    }
    return sum;
}
void solve(int32_t N, int32_t k, long long A, int32_t S) {
    cnt = 50;
    n = N;

    int l,r;

    l = 1;
    r = n;
    int p = -1;
    while(l <= r) {
        int mid = (l+r)/2;
        if(qry(mid) >= A) {
            r = mid-1;
            p = mid;
        }
        else {
            l = mid+1;
        }
    }

    if(p != -1) {
        if(p < k) {
            impossible();
            return;
        }
        if(qrysum(1,k-1)+qry(p) <= 2*A) {
            vector<int32_t> ans;
            for(int j = 1; j <= k-1; j++) ans.pb(j);
            ans.pb(p);
            answer(ans);
            return;
        }

        if(p == k) {
            impossible();
            return;
        }
        n = p-1;
        // n is >= k
    }

    int sumcur = qrysum(1,k);
    if(sumcur > 2*A) {
        impossible();
        return;
    }
    if(sumcur >= A) {
        vector<int32_t> ans;
        for(int j = 1; j <= k; j++) ans.pb(j);
        answer(ans);
        return;
    }

    for(int i = 0; i <= k; i++) {
        if(qrysum(1,i)+qrysum(n-(k-i)+1,n) >= A && qrysum(1,i)+qrysum(n-(k-i)+1,n) <= 2*A) {
            vector<int32_t> ans;
            for(int j = 1; j <= i; j++) ans.pb(j);
            for(int j = n-(k-i)+1; j <= n; j++) ans.pb(j);
            answer(ans);
            return;
        }
    }

    // vector<int32_t> ans;
    // for(int i = k; i >= 1; i--) {
    //     if(sumcur-qry(i)+qry(n) < A) {
    //         sumcur = sumcur-qry(i)+qry(n);
    //         ans.pb(n);
    //         n--;
    //     }
    //     else if(sumcur-qry(i)+qry(n) <= 2*A) {
    //         //I found the answer
    //         ans.pb(n);
    //         for(int j = 1; j < i; j++) ans.pb(j);
    //         sort(all(ans));
    //         answer(ans);
    //         return;
    //     }
    // }

    impossible();
}
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...