This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include "vision.h"
using namespace std;
typedef long long ll;
void construct_network(int h, int w, int k)
{
vector<int> rd1(h + w - 1), rd2(h + w - 1);
vector<int> ld1(h + w - 1), ld2(h + w - 1);
for (int d = 0; d < h + w - 1; d++)
{
// right-diagonal of (i, j) = i + j
vector<int> idx;
for (int i = 0; i < h; i++)
if (0 <= d - i && d - i < w)
idx.push_back(i * w + d - i);
// rd1 : is there at least one black pixel on this diagonal?
rd1[d] = add_or(idx);
// rd2 : are there exactly two black pixels on this diagonal?
rd2[d] = add_xor({add_xor(idx), rd1[d]});
// left-diagonal of (i, j) = i - j + (w - 1)
idx.clear();
for (int i = 0; i < h; i++)
if (0 <= i - d + w - 1 && i - d + w - 1 < w)
idx.push_back(i * w + i - d + w - 1);
// ld1 : is there at least one black pixel on this diagonal?
ld1[d] = add_or(idx);
// ld2 : are there exactly two black pixels on this diagonal?
ld2[d] = add_xor({add_xor(idx), rd1[d]});
}
vector<int> A, B, C, D;
for (int d = 0; d + k < h + w - 1; d++)
{
vector<int> idxR1, idxR2, idxL1, idxL2;
for (int i = 0; i < k + 1; i++)
{
idxR1.push_back(rd1[d + i]);
idxR2.push_back(rd2[d + i]);
idxL1.push_back(ld1[d + i]);
idxL2.push_back(ld2[d + i]);
}
A.push_back(add_or({add_xor({add_or(idxR1), add_xor(idxR1)}),add_or(idxR2)}));
B.push_back(add_or({add_xor({add_or(idxL1), add_xor(idxL1)}),add_or(idxL2)}));
}
for (int d = 0; d + k - 1 < h + w - 1; d++)
{
vector<int> idxR1, idxR2, idxL1, idxL2;
for (int i = 0; i < k; i++)
{
idxR1.push_back(rd1[d + i]);
idxR2.push_back(rd2[d + i]);
idxL1.push_back(ld1[d + i]);
idxL2.push_back(ld2[d + i]);
}
C.push_back(add_or({add_xor({add_or(idxR1), add_xor(idxR1)}),add_or(idxR2)}));
D.push_back(add_or({add_xor({add_or(idxL1), add_xor(idxL1)}),add_or(idxL2)}));
}
int x = add_and({add_or(A), add_or(B)});
int y = add_and({add_or(C), add_or(D)});
add_and({x, add_not(y)});
}
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