이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define all(x) x.begin(), x.end()
#define sz(x) (int) x.size()
#define endl '\n'
#define pb push_back
#define _ ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
using namespace std;
using ll = long long;
using ull = unsigned long long;
using ii = pair<int,int>;
using iii = tuple<int,int,int>;
const int inf = 2e9+1;
const int mod = 1e9+7;
const int maxn = 1e4+1;
template<typename X, typename Y> bool ckmin(X& x, const Y& y) { return (y < x) ? (x=y,1):0; }
template<typename X, typename Y> bool ckmax(X& x, const Y& y) { return (x < y) ? (x=y,1):0; }
int a[maxn], where[maxn], ans[maxn][101], resp[100];
int main(){_
int n,l;cin>>n>>l;
for(int i=1;i<=n;++i)cin>>a[i];
int q;cin>>q;
vector<ii>qu(q);
for(int i=0;i<q;++i)cin>>qu[i].first, qu[i].second = i;
sort(all(qu));
int i = 0;
for(int j=0;j<q;++j)
while(i!=qu[j].first)++i, where[i] = j;
while(i!=l)++i, where[i] = q+1;
for(int i=1;i<=n-l;++i){//distance from two strings
int x = 1, y = 1 + i, cur = 0;
for(int j=0;j<l;++j)cur += (a[j+1]!=a[i+j+1]);
ans[x++][where[cur]]++, ans[y++][where[cur]]++;
while(y+l-1<=n){
cur += (a[x+l-1]!=a[y+l-1])-(a[x-1]!=a[y-1]);
ans[x++][where[cur]]++, ans[y++][where[cur]]++;
}
}
for(int i=1;i<=n-l+1;++i)
for(int j=1;j<q;++j)
ans[i][j] += ans[i][j-1];
sort(all(qu), [&](ii x,ii y){return x.second<y.second;});
for(auto [a,b]:qu)
for(int i=1;i<=n-l+1;++i)cout<<ans[i][where[a]]<<" \n"[i==n-l+1];
}
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