제출 #656099

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
656099		Soul234	오벨리스크 (NOI14_obelisk)	C++14	25 / 25	78 ms	24668 KiB

obelisk

#include<bits/stdc++.h>
using namespace std;

void DBG() { cerr << "]\n"; }
template<class H, class... T> void DBG(H h, T... t) {
    cerr << h; if(sizeof...(t)) cerr << ", ";
    DBG(t...);
}
#ifdef LOCAL
#define dbg(...) cerr << "[" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define dbg(...) 0
#endif // LOCAL

#define FOR(i,a,b) for(int i = (a) ; i<(b) ; i++)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for(int i = (b)-1 ; i>=(a) ; i--)
#define R0F(i,a) ROF(i,0,a)
#define each(e,a) for(auto &e : (a))
#define sz(v) (int)(v).size()
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define pb push_back
#define tcT template<class T
#define nl "\n"
#define fi first
#define se second

using ll = long long;
using vi = vector<int>;
using pi = pair<int,int>;
using str = string;
using db = long double;
tcT> using V = vector<T>;
tcT> using pqg = priority_queue<T,vector<T>,greater<T>>;

void setIO(string NAME = "") {
    cin.tie(0)->sync_with_stdio(0);
    if(sz(NAME)) {
        freopen((NAME + ".inp").c_str(),"r",stdin);
        freopen((NAME + ".out").c_str(),"w",stdout);
    }
}

tcT> bool ckmin(T&a, const T&b) {
    return b < a ? a=b,1 : 0; }
tcT> bool ckmax(T&a, const T&b) {
    return b > a ? a=b,1 : 0; }

const int MOD = 1e9 + 7;
const ll INF = 1e18;


const int MX = 505;
int K, M;

V<pi> lst[MX];

int sx, sy, ex, ey;
int inds[MX];

V<pi> adj[MX*MX];

ll dist[MX*MX];

void dijkstra(int src) {
    memset(dist, 0x3f, sizeof dist);
    pqg<pair<ll,int>> pq;
    pq.push({dist[src] = 0, src});
    while(sz(pq)) {
        ll du = pq.top().fi;
        int u = pq.top().se;
        pq.pop();
        if(du > dist[u]) continue;
        each(ed, adj[u]) {
            int v = ed.fi;
            ll dv = dist[u] + ed.se;
            if(ckmin(dist[v], dv)) {
                pq.push({dv, v});
            }
        }
    }
}

int dist1D(int delta, bool hor, bool ver) {
    if(M == 1) return delta;
    if(delta == 0) return 0;
    if(!hor && !ver) return MOD;
    if(!hor) return delta;
    int need = delta/(M+1);
    int sx = need*(M+1);
    if(delta == sx) return 2*need - 2;
    if(!ver) return MOD;
    int opt1 = max(0, 2*need - 2) + delta - sx;
    int opt2 = 2*need + sx + M + 1 - delta;
    return min(opt1, opt2);
}

int dist2D(int dx, int dy) {
    int res = INT_MAX;
    F0R(i, 2) F0R(j, 2) {
        ckmin(res, 2*(i + j) + dist1D(dx, i, j) + dist1D(dy, j, i));
    }
    return res;
}

void solve() {
    cin >> K >> M;
    cin >> sx >> sy >> ex >> ey;
    lst[0] = {{ex, ey}};
    lst[K] = {{sx, sy}};
    ROF(i,1,K) {
        int num;
        cin >> num;
        lst[i].resize(num);
        F0R(j, num) {
            cin >> lst[i][j].fi >> lst[i][j].se;
        }
    }
    F0R(i, K) inds[i+1] = inds[i] + sz(lst[i]);
    FOR(fl,1,K+1) {
        F0R(i, sz(lst[fl]))
            F0R(j, sz(lst[fl-1])) {
                int dx = abs(lst[fl][i].fi - lst[fl-1][j].fi), dy = abs(lst[fl][i].se - lst[fl-1][j].se);
//                dbg(dx, dy, dist2D(dx, dy));
                adj[inds[fl]+i].pb({inds[fl-1]+j, dist2D(dx, dy)});
            }
    }
//    dbg(dist1D(1));
    dijkstra(inds[K]);
    cout << dist[0] << nl;
}

int main() {
    setIO();

    int t=1;
    //cin>>t;
    while(t-->0) {
        solve();
    }

    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

obelisk.cpp: In function 'void setIO(std::string)':
obelisk.cpp:40:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   40 |         freopen((NAME + ".inp").c_str(),"r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
obelisk.cpp:41:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   41 |         freopen((NAME + ".out").c_str(),"w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 5 / 5
• Subtask 2: 7 / 7
• Subtask 3: 6 / 6
• Subtask 4: 7 / 7