제출 #655294

#제출 시각아이디문제언어결과실행 시간메모리
655294ssenseGap (APIO16_gap)C++14
100 / 100
62 ms1876 KiB
#include <bits/stdc++.h>
#include "gap.h"
#define startt ios_base::sync_with_stdio(false);cin.tie(0);
typedef long long  ll;
using namespace std;
#define vint vector<int>
#define all(v) v.begin(), v.end()
#define MOD 1000000007
#define MOD2 998244353
#define MX 1000000000
#define MXL 1000000000000000000
#define PI (ld)2*acos(0.0)
#define pb push_back
#define sc second
#define fr first
//#define int long long
#define endl '\n'
#define ld long double
#define NO cout << "NO" << endl
#define YES cout << "YES" << endl

long long findGap(int T, int N)
{
    if(T == 1)
    {
        long long mn, mx;
        long long ask1 = 0, ask2 = 1e18;
        vector<long long> a(N);
        for(int i = 0; i < N; i++)
        {
            a[i] = -1;
        }
        long long nowi = 0, nowi2 = N-1;
        while(true)
        {
            if(nowi > nowi2)
            {
                break;
            }
            MinMax(ask1, ask2, &mn, &mx);
            if(mn == -1 && mx == -1)
            {
                break;
            }
            if(mn == mx)
            {
                a[nowi] = mn;
                break;
            }
            a[nowi] = mn;
            nowi++;
            a[nowi2] = mx;
            nowi2--;
            ask1 = mn+1;
            ask2 = mx-1;
        }
        long long ans = 0;
        for(int i = 0; i < N-1; i++)
        {
            assert(a[i] != -1);
            ans = max(ans, a[i+1]-a[i]);
        }
        return ans;
    }
    else
    {
        long long mn, mx;
        MinMax(0, 1e18, &mn, &mx);
        long long size = mx-mn-1;
        long long nowmin = mn+1, last = mn;
        long long ans = size/(N-1);
        for(int i = 0; i < N-1; i++)
        {
            long long nowmax = nowmin+size/(N-1);
            MinMax(nowmin, nowmax, &mn, &mx);
            if(mn != -1)
            {
                ans = max(ans, mn-last);
                last = mx;
            }
            nowmin = nowmax+1;
        }
        return ans;
    }
}
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