제출 #654812

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
654812		t6twotwo	Catfish Farm (IOI22_fish)	C++17	52 / 100	897 ms	2097152 KiB

fish

#include "fish.h"
#include <bits/stdc++.h>
using namespace std;
const long long inf = -(1LL << 50);
long long max_weights(int n, int m, vector<int> x, vector<int> y, vector<int> w) {
  vector P(n, vector<int>(n + 1));
  for (int i = 0; i < m; i++) {
    P[x[i]][y[i] + 1] = w[i];
  }
  vector s(n, vector<long long>(n + 2));
  for (int i = 0; i < n; i++) {
    for (int j = 0; j <= n; j++) {
      s[i][j + 1] = s[i][j] + P[i][j];
    }
  }
  auto range_sum = [&](int i, int l, int r) -> long long {
    if (i == -1) {
      return 0;
    }
    return s[i][r + 1] - s[i][l + 1];
  };
  vector d(n, vector<int>{0});
  for (int i = 0; i < n; i++) {
    for (int j = 1; j <= n; j++) {
      d[i].push_back(j);
    }
  }
  vector<int> e{0};
  vector<array<long long, 2>> dp{{0, 0}};
  for (int i = 0; i < n; i++) {
    auto pd = dp;
    int l = d[i].size();
    dp = vector(l, array<long long, 2>{inf, inf});
    int k = pd.size();
    vector<long long> pmax(k + 1, inf);
    for (int j = 0; j < k; j++) {
      pmax[j + 1] = max(pmax[j], pd[j][0] + range_sum(i - 1, e[j], n)); //suf_sum(i - 1, e[j]));
      dp[0][0] = max(dp[0][0], max(pd[j][0], pd[j][1]));
      dp[0][1] = max(dp[0][1], max(pd[j][0], pd[j][1]) + range_sum(i, 0, e[j])); //pre_sum(i, e[j]));
    }
    vector<long long> smax(k + 1, inf);
    for (int j = k - 1; j >= 0; j--) {
      smax[j] = max(smax[j + 1], max(pd[j][0], pd[j][1]) - range_sum(i, e[j], n)); //suf_sum(i, e[j]));
    }
    for (int j = 1; j < l; j++) {
      dp[j][0] = max({dp[j][0], max(pd[0][1], pd[0][0] + range_sum(i - 1, 0, d[i][j]) /*pre_sum(i - 1, d[i][j])*/), pmax[upper_bound(e.begin(), e.end(), d[i][j]) - e.begin()] - range_sum(i - 1, d[i][j], n)}); //suf_sum(i - 1, d[i][j])});
      dp[j][1] = max({dp[j][1], max(pd[0][1], pd[0][0] + range_sum(i - 1, 0, d[i][j]) /*pre_sum(i - 1, d[i][j])*/), smax[lower_bound(e.begin(), e.end(), d[i][j]) - e.begin()] + range_sum(i, d[i][j], n)}); //suf_sum(i, d[i][j])});
    }
    e.swap(d[i]);
  }
  long long ans = inf;
  for (auto v : dp) {
    ans = max(ans, max(v[0], v[1]));
  }
  return ans;
}

• Subtask 1: 0 / 3
• Subtask 2: 0 / 6
• Subtask 3: 0 / 9
• Subtask 4: 14 / 14
• Subtask 5: 21 / 21
• Subtask 6: 17 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16