이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define dbg(x) cerr << #x << " " << x << endl;
#define ll long long
const int maxN = 2e5 + 10, LOG = 22, inf = 1e8;
int h[maxN], n, pre[maxN][LOG], nxt[maxN][LOG];
int mx[maxN][LOG];
struct segTree {
vector<pair<long long, int>> mTree;
int size;
void init(long long n) {
size = 1;
while(size < n) {
size *= 2;
}
mTree.assign(2 * size - 1, {0, 0});
}
pair<ll, ll> combine(pair<ll, ll> a, pair<ll, ll> b) {
if(a.first > b.first) {
return a;
} else {
return b;
}
}
void upd(int u, long long v, int x, int lx, int rx) { // set value at pos u
if(rx - lx == 1) {
mTree[x] = {v, lx};
return;
}
int m = (lx + rx) / 2;
if(u < m) {
upd(u, v, 2 * x + 1, lx, m);
}else {
upd(u, v, 2 * x + 2, m, rx);
}
mTree[x] = combine(mTree[2 * x + 1], mTree[2 * x + 2]);
}
void upd(int u, long long v) {
upd(u, v, 0, 0, size);
}
pair<ll, ll> qry (int l, int r, int x, int lx, int rx) { // range queries
if(l >= rx || lx >= r) {
return {INT64_MIN, -1};
}
if(lx >= l && r >= rx) {
return mTree[x];
}
int m = (rx + lx) / 2;
auto s1 = qry(l, r, 2 * x + 1, lx, m);
auto s2 = qry(l, r, 2 * x + 2, m, rx);
return combine(s1, s2);
}
pair<ll, ll> qry(int l, int r) {
return qry(l, r, 0, 0, size);
}
};
segTree seg;
void init(int N, std::vector<int> H) {
n = N, seg.init(n + 1);
for(int i = 0; i < N; i++) {
h[i] = H[i];
seg.upd(i, h[i]);
//
nxt[i][0] = pre[i][0] = i;
}
stack<pair<int, int>> st;
for(int i = 0; i < N; i++) {
while(!st.empty() && h[i] > st.top().first) {
nxt[st.top().second][0] = i;
st.pop();
}
st.push({h[i], i});
}
while(!st.empty()) st.pop();
for(int i = N - 1; i >= 0; i--) {
while(!st.empty() && h[i] > st.top().first) {
pre[st.top().second][0] = i;
st.pop();
}
st.push({h[i], i});
}
for(int i = 0; i < N; i++) {
if(h[nxt[i][0]] >= h[pre[i][0]]) {
mx[i][0] = nxt[i][0];
} else {
mx[i][0] = pre[i][0];
}
}
for(int j = 1; j < LOG; j++) {
for(int i = 0; i < N; i++) {
mx[i][j] = mx[mx[i][j - 1]][j - 1];
nxt[i][j] = nxt[nxt[i][j - 1]][j - 1];
pre[i][j] = pre[pre[i][j - 1]][j - 1];
}
}
}
int get_mx(int mid, int node) {
for(int i = 0; i < LOG; i++) {
if(mid & (1 << i)) {
node = mx[node][i];
}
}
return node;
}
int get_r(int mid, int node) {
for(int i = 0; i < LOG; i++) {
if(mid & (1 << i)) {
node = nxt[node][i];
}
}
return node;
}
int minimum_jumps(int A, int B, int C, int D) {
auto maxim = seg.qry(B, C);
auto maxim_ = seg.qry(C, D + 1);
if(maxim.first >= maxim_.first) {
return -1;
}
int l = A, r = B, st = -1;
while(l <= r) {
int mid = (l + r) / 2;
if(seg.qry(mid, r + 1).first < maxim_.first) {
st = mid;
r = mid - 1;
} else {
l = mid + 1;
}
}
if(st == -1) {
return -1;
}
A = seg.qry(st, B + 1).second;
int ina = 0, inb = maxN, answ = 0;
while(ina <= inb) {
int mid = (ina + inb) / 2;
int pos = get_mx(mid, A);
if(h[pos] >= maxim.first) {
answ = mid;
inb = mid - 1;
} else {
ina = mid + 1;
}
}
int pos = get_mx(answ, A);
if(pos >= C && pos <= D) return answ;
if(h[pos] >= maxim_.first) { answ--; }
pos = get_mx(answ, A);
ina = 0, inb = maxN;
int answ2 = 0;
while(ina <= inb) {
int mid = (ina + inb) / 2;
int pos2 = get_r(mid, pos);
if(pos2 >= C) {
answ2 = mid;
inb = mid - 1;
} else {
ina = mid + 1;
}
}
pos = get_r(answ2, pos);
return answ2 + answ;
}
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