이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#ifdef ONPC
mt19937 rng(228);
#else
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());
#endif
signed main() {
#ifndef ONPC
ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#endif
int n, m;
cin >> n >> m;
vector<int> a(n), pos(n), b(m);
for (int i = 0; i < n; i++) {
int x;
cin >> x;
x--;
a[x] = i;
pos[i] = x;
}
for (int i = 0; i < m; i++) {
cin >> b[i];
}
if (0) {
cout << "a = ";
for (int i = 0; i < n; i++) {
cout << a[i] << " ";
}
cout << "\n";
}
vector<int> small(n, -1), big(n, -1);
vector<int> urm(n, -1), ant(n, -1);
for (int i = 0; i < n - 1; i++) {
urm[i] = i + 1;
ant[i + 1] = i;
}
for (int i = n - 1; i >= 0; i--) {
int x = a[i];
if (ant[x] != -1) {
small[i] = i - pos[ant[x]];
}
if (urm[x] != -1) {
big[i] = i - pos[urm[x]];
}
int a = ant[x], b = urm[x];
if (b != -1) ant[b] = a;
if (a != -1) urm[a] = b;
}
int cnt = 0;
function<int(vector<int>&, int, int)> isok = [&] (vector<int> &v, int pos, int j) {
//cout << " = " << pos << " " << j << ", " << small[j] << " " << big[j] << "\n";
//cnt++;
if (cnt == 2) {
//exit(0);
}
// cout << " : " << pos << " out of " << (int) v.size() << "\n";
assert(0 <= j && j < n);
assert(0 <= pos && pos < (int) v.size());
if (small[j] != -1) {
assert(pos - small[j] >= 0);
}
if (big[j] != -1) {
assert(pos - big[j] >= 0);
}
if (small[j] != -1 && v[pos] < v[pos - small[j]]) {
return 0;
}
if (big[j] != -1 && v[pos] > v[pos - big[j]]) {
return 0;
}
return 1;
};
vector<int> ps(n, 0);
int j = 0;
for (int i = 1; i < n; i++) {
while (j && !isok(a, i, j)) {
j = ps[j - 1];
}
if (isok(a, i, j)) {
j++;
}
ps[i] = j;
}
//exit(0);
vector<int> sol;
j = 0;
for (int i = 0; i < m; i++) {
while (j && !isok(b, i, j)) {
j = ps[j - 1];
}
if (isok(b, i, j)) {
j++;
}
if (j == n) {
sol.push_back(i - n + 2);
j = ps[j - 1];
}
}
cout << (int) sol.size() << "\n";
for (auto &i : sol) {
cout << i << " ";
}
cout << "\n";
return 0;
}
/*
input =
5 10
2 1 5 3 4
5 6 3 8 12 7 1 10 11 9
output =
2
2 6
*/
/* stuff you should look for
* int overflow, array bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH
*/
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