제출 #653739

#제출 시각아이디문제언어결과실행 시간메모리
653739600MihneaMatching (CEOI11_mat)C++17
100 / 100
363 ms48148 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; #ifdef ONPC mt19937 rng(228); #else mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); #endif signed main() { #ifndef ONPC ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); #endif int n, m; cin >> n >> m; vector<int> a(n), pos(n), b(m); for (int i = 0; i < n; i++) { int x; cin >> x; x--; a[x] = i; pos[i] = x; } for (int i = 0; i < m; i++) { cin >> b[i]; } if (0) { cout << "a = "; for (int i = 0; i < n; i++) { cout << a[i] << " "; } cout << "\n"; } vector<int> small(n, -1), big(n, -1); vector<int> urm(n, -1), ant(n, -1); for (int i = 0; i < n - 1; i++) { urm[i] = i + 1; ant[i + 1] = i; } for (int i = n - 1; i >= 0; i--) { int x = a[i]; if (ant[x] != -1) { small[i] = i - pos[ant[x]]; } if (urm[x] != -1) { big[i] = i - pos[urm[x]]; } int a = ant[x], b = urm[x]; if (b != -1) ant[b] = a; if (a != -1) urm[a] = b; } int cnt = 0; function<int(vector<int>&, int, int)> isok = [&] (vector<int> &v, int pos, int j) { //cout << " = " << pos << " " << j << ", " << small[j] << " " << big[j] << "\n"; //cnt++; if (cnt == 2) { //exit(0); } // cout << " : " << pos << " out of " << (int) v.size() << "\n"; assert(0 <= j && j < n); assert(0 <= pos && pos < (int) v.size()); if (small[j] != -1) { assert(pos - small[j] >= 0); } if (big[j] != -1) { assert(pos - big[j] >= 0); } if (small[j] != -1 && v[pos] < v[pos - small[j]]) { return 0; } if (big[j] != -1 && v[pos] > v[pos - big[j]]) { return 0; } return 1; }; vector<int> ps(n, 0); int j = 0; for (int i = 1; i < n; i++) { while (j && !isok(a, i, j)) { j = ps[j - 1]; } if (isok(a, i, j)) { j++; } ps[i] = j; } //exit(0); vector<int> sol; j = 0; for (int i = 0; i < m; i++) { while (j && !isok(b, i, j)) { j = ps[j - 1]; } if (isok(b, i, j)) { j++; } if (j == n) { sol.push_back(i - n + 2); j = ps[j - 1]; } } cout << (int) sol.size() << "\n"; for (auto &i : sol) { cout << i << " "; } cout << "\n"; return 0; } /* input = 5 10 2 1 5 3 4 5 6 3 8 12 7 1 10 11 9 output = 2 2 6 */ /* stuff you should look for * int overflow, array bounds * special cases (n=1?) * do smth instead of nothing and stay organized * WRITE STUFF DOWN * DON'T GET STUCK ON ONE APPROACH */
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