제출 #653073

#제출 시각아이디문제언어결과실행 시간메모리
653073ssense수열 (APIO14_sequence)C++14
100 / 100
990 ms97304 KiB
#include <bits/stdc++.h> #define startt ios_base::sync_with_stdio(false);cin.tie(0); typedef long long ll; using namespace std; #define vint vector<int> #define aint(v) v.begin(), v.end() #define MOD 1000000007 #define MOD2 998244353 #define MX 1000000000 #define MXL 1000000000000000000 #define PI (ld)2*acos(0.0) #define pb push_back #define sc second #define fr first //#define int long long #define endl '\n' #define ld long double #define NO cout << "NO" << endl #define YES cout << "YES" << endl int ceildiv(int one, int two) {if (one % two == 0) {return one / two;}else {return one / two + 1;}} int power(int n, int pow, int m) {if (pow == 0) return 1;if (pow % 2 == 0) {int x = power(n, pow / 2, m);return (x * x) % m;}else return (power(n, pow - 1, m) * n) % m;} int gcd(int a, int b) { if (!b)return a; return gcd(b, a % b);} int factorial(int n, int mod) {if (n > 1)return (n * factorial(n - 1, mod)) % mod; else return 1;} int lcm(int a, int b) {return (a * b) / gcd(a, b);} vector<ll> read(ll n) {vector<ll> a; for (int i = 0; i < n; i++) { int x; cin >> x; a.pb(x);} return a;}struct prefix_sum{vector<ll> pref;void build(vector<ll> a){pref.pb(0LL);for(int i = 0; i < a.size(); i++){pref.pb(pref.back()+a[i]);}}ll get(ll l, ll r){return pref[r]-pref[l-1];}};//mesanu const int K = 200; const int N = 1e5; int best[N+5][K+5]; deque<pair<pair<ll, ll>, ll>> lines[K+5]; const double eps = 1e-5; long double intersection_point(ll first_slope, ll first_b, ll second_slope, ll second_b) { return (long double)(second_b-first_b)/(long double)(first_slope-second_slope); } void insert(ll m, ll b, ll k, ll index) { if(m == lines[k].front().fr.fr) { if(b > lines[k].front().fr.sc) { lines[k].pop_front(); } else { return; } } while(lines[k].size() > 1 && intersection_point(m, b, lines[k].front().fr.fr, lines[k].front().fr.sc)+eps > intersection_point(lines[k].front().fr.fr, lines[k].front().fr.sc, lines[k][1].fr.fr, lines[k][1].fr.sc)) { lines[k].pop_front(); } lines[k].push_front({{m, b}, index}); } pair<ll, int> get_line(ll x, ll k) { while(lines[k].size() >= 2 && lines[k].back().fr.fr*x+lines[k].back().fr.sc <= lines[k][lines[k].size()-2].fr.fr*x + lines[k][lines[k].size()-2].fr.sc) { lines[k].pop_back(); } return {lines[k].back().fr.fr*x+lines[k].back().fr.sc, lines[k].back().sc}; } void solve() { int n, k; cin >> n >> k; vector<ll> a = read(n); prefix_sum pref; pref.build(a); for(int i = 0; i <= k; i++) { deque<pair<pair<ll, ll>, ll>> x; x.push_back({{0, 0}, 0}); lines[i] = x; } ll ans = 0; int start = 0; for(int i = 0; i < n-1; i++) { vector<ll> now_vals(k+1); for(int j = min(k, i+1); j >= 1; j--) { pair<ll, int> best_line = get_line(pref.get(i+2, n), j-1); now_vals[j] = best_line.fr+pref.get(1, i+1)*pref.get(i+2, n); best[i+1][j] = best_line.sc; if(now_vals[j] >= ans && j == k) { start = i+1; ans = now_vals[j]; } insert(-pref.get(1, i+1), now_vals[j], j, i+1); } } cout << ans << endl; while(k != 0) { cout << start << " "; start = best[start][k--]; } cout << endl; } int32_t main(){ startt int t = 1; //cin >> t; while (t--) { solve(); } } /* 7 3 4 1 3 4 0 2 3 */ /* introduci o linie - m = -sum 0..i b = dp[i][k] get o linie - k = k-1 coordonatul sum i..n */

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In member function 'void prefix_sum::build(std::vector<long long int>)':
sequence.cpp:20:679: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   20 | int ceildiv(int one, int two) {if (one % two == 0) {return one / two;}else {return one / two + 1;}} int power(int n, int pow, int m) {if (pow == 0) return 1;if (pow % 2 == 0) {int x = power(n, pow / 2, m);return (x * x) % m;}else return (power(n, pow - 1, m) * n) % m;} int gcd(int a, int b) { if (!b)return a; return gcd(b, a % b);} int factorial(int n, int mod) {if (n > 1)return (n * factorial(n - 1, mod)) % mod; else return 1;} int lcm(int a, int b) {return (a * b) / gcd(a, b);} vector<ll> read(ll n) {vector<ll> a; for (int i = 0; i < n; i++) { int x; cin >> x; a.pb(x);} return a;}struct prefix_sum{vector<ll> pref;void build(vector<ll> a){pref.pb(0LL);for(int i = 0; i < a.size(); i++){pref.pb(pref.back()+a[i]);}}ll get(ll l, ll r){return pref[r]-pref[l-1];}};//mesanu
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