| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 65266 | KHUSRAV | Boxes with souvenirs (IOI15_boxes) | C++14 | 2 ms | 380 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "boxes.h"
#include<bits/stdc++.h>
using namespace std ;
pair<long long , long long> dppred[10000001] , dpfirst[10000001];
long long delivery(int N, int K, int L, int p[]) {
    deque<int> dq ;
    if(p[0] <= L / 2){
        dppred[0] = {p[0] * 2 , K - 1};
        dpfirst[0] = {p[0] * 2 , K - 1};
    }
    else{
        dppred[0] = {(L - p[0]) * 2 , K - 1};
        dpfirst[0] = {(L - p[0]) * 2 , K - 1};
    }
    for(int i = 1 ; i < N ; i++){
        if(p[i] <= L / 2){
            dppred[i] = {p[i] * 2 + dppred[i - 1].first, K - 1};
            dpfirst[i] = {p[i] * 2 + dppred[i - 1].first, K - 1};
        }
        else{
            dppred[i] = {(L - p[i]) * 2 + dppred[i - 1].first, K - 1};
            dpfirst[i] = {(L - p[i]) * 2 + dppred[i - 1].first, K - 1};
        }
        if(dppred[i - 1].second > 0){
            int k = dppred[i - 1].second;
            int l = p[i - 1];
            int s = dppred[i - 1].first , g;
            if(l <= L / 2)
                g = l;
            else g = L - l ;
            if(p[i] <= L / 2){
                if(dppred[i].first > s - g + (p[i] - p[i - 1]) + p[i]){
                    dppred[i].first = s - g + (p[i] - p[i - 1]) + p[i];
                    dppred[i].second = dppred[i - 1].second - 1 ;
                }
            }
            else{
                if(dppred[i].first > s - g + (p[i] - p[i - 1]) + L - p[i]){
                    dppred[i].first = s - g + (p[i] - p[i - 1]) + L - p[i];
                    dppred[i].second = dppred[i - 1].second - 1 ;
                }
            }
        }
        if(dpfirst[i - 1].second > 0){
            int k = dpfirst[i - 1].second;
            int l = p[i - 1];
            int s = dpfirst[i - 1].first , g;
            if(l <= L / 2)
                g = l;
            else g = L - l ;
            if(p[i] <= L / 2){
                if(dppred[i].first > s - g + (p[i] - p[i - 1]) + p[i]){
                    dppred[i].first = s - g + (p[i] - p[i - 1]) + p[i];
                    dppred[i].second = dpfirst[i - 1].second - 1 ;
                }
            }
            else{
                if(dpfirst[i].first > s - g + (p[i] - p[i - 1]) + L - p[i]){
                    dppred[i].first = s - g + (p[i] - p[i - 1]) + L - p[i];
                    dppred[i].second = dpfirst[i - 1].second - 1 ;
                }
            }
        }
    }
    return dppred[N - 1].first ;
}
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