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답안 #651759

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
651759 2022-10-20T01:38:38 Z ghostwriter 열대 식물원 (Tropical Garden) (IOI11_garden) C++14
69 / 100
 5000 ms 16848 KB 
#pragma GCC optimize ("Ofast")
#pragma GCC target ("avx2")
#include "garden.h"
#include "gardenlib.h"
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#include <debug.h>
#include "grader.cpp"
#else
#define debug(...)
#endif
#define ft front
#define bk back
#define st first
#define nd second
#define ins insert
#define ers erase
#define pb push_back
#define pf push_front
#define _pb pop_back
#define _pf pop_front
#define lb lower_bound
#define ub upper_bound
#define mtp make_tuple
#define bg begin
#define ed end
#define all(x) x.bg(), x.ed()
#define sz(x) (int)x.size()
typedef long long ll; typedef unsigned long long ull;
typedef double db; typedef long double ldb;
typedef pair<int, int> pi; typedef pair<ll, ll> pll;
typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pi> vpi; typedef vector<pll> vpll;
typedef string str;
template<typename T> T gcd(T a, T b) { return (b == 0? a : gcd(b, a % b)); }
template<typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
#define FOR(i, l, r) for (int i = l; i <= r; ++i)
#define FOS(i, r, l) for (int i = r; i >= l; --i)
#define FRN(i, n) for (int i = 0; i < n; ++i)
#define FSN(i, n) for (int i = n - 1; i >= 0; --i)
#define EACH(i, x) for (auto &i : x)
#define WHILE while
#define file "TEST"
mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());
ll rand(ll l, ll r) { return uniform_int_distribution<ll>(l, r)(rd); }
/*
----------------------------------------------------------------
    END OF TEMPLATE
----------------------------------------------------------------
    Tran The Bao - ghostwriter
    Training for VOI23 gold medal
----------------------------------------------------------------
    GOAT
----------------------------------------------------------------
*/
const int MAXN = 15e4;
int ind[MAXN][2], c[MAXN][2], c1[MAXN][2], s[MAXN][2], d[MAXN][2];
vi adj[MAXN];
vpi e;
pi nxt(pi x) {
    int u = x.st;
    bool stt = x.nd;
    int id = (!stt? 0 : sz(adj[u]) == 1? 0 : 1);
    int nxtv = e[adj[u][id]].st == u? e[adj[u][id]].nd : e[adj[u][id]].st;
    return {nxtv, adj[u][id] == adj[nxtv][0]? 1 : 0};
}
int cal(int &N, int &P, int &x) {
    memset(c, 0, sizeof c);
    int ans = 0;
    FRN(i, N)
    FRN(j, 2) {
        if (ind[i][j]) continue;
        int x1 = x;
        if (x1 > d[i][j]) {
            x1 -= d[i][j];
            x1 %= s[i][j];
            x1 += d[i][j];
        }
        pi cur = {i, j};
        FOR(z, 1, x1) cur = nxt(cur);
        if (cur.st == P && !j) ++ans;
        c[i][j] = 1;
        pi cur1 = nxt({i, j});
        WHILE(!c[cur1.st][cur1.nd]) {
            cur = nxt(cur);
            if (cur.st == P && !cur1.nd) ++ans;
            c[cur1.st][cur1.nd] = 1;
            cur1 = nxt(cur1);
        }
    }
    FRN(i, N)
    FRN(j, 2) {
        if (c[i][j]) continue;
        int x1 = x % s[i][j];
        pi cur = {i, j};
        FOR(z, 1, x1) cur = nxt(cur);
        if (cur.st == P && !j) ++ans;
        c[i][j] = 1;
        pi cur1 = nxt({i, j});
        WHILE(!c[cur1.st][cur1.nd]) {
            cur = nxt(cur);
            if (cur.st == P && !cur1.nd) ++ans;
            c[cur1.st][cur1.nd] = 1;
            cur1 = nxt(cur1);
        }   
    }
    return ans;
}
void count_routes(int N, int M, int P, int R[][2], int Q, int G[]) {
    FRN(i, M) {
        int u = R[i][0], v = R[i][1];
        e.pb({u, v});
        if (sz(adj[u]) < 2) adj[u].pb(i);
        if (sz(adj[v]) < 2) adj[v].pb(i);
    }
    FRN(i, N)
    FRN(j, 2) {
        pi tmp1 = nxt({i, j});
        ind[tmp1.st][tmp1.nd] = 1;
        if (c1[i][j]) continue;
        vpi ver;
        pi cur = {i, j};
        WHILE(1) {
            if (!c[cur.st][cur.nd]) ver.pb(cur);
            ++c[cur.st][cur.nd];
            cur = nxt(cur);
            if (c1[cur.st][cur.nd] || c[cur.st][cur.nd] == 2) break;
        }
        reverse(all(ver));
        if (c[ver.ft().st][ver.ft().nd] == 2) {
            int cnt = 0, h = 0;
            EACH(z, ver) if (c[z.st][z.nd] == 2) ++cnt;
            EACH(z, ver) {
                if (c[z.st][z.nd] == 1) ++h;
                s[z.st][z.nd] = cnt;
                d[z.st][z.nd] = h;
            }
        }
        else {
            pi tmp = nxt(ver.ft());
            int cnt = s[tmp.st][tmp.nd], h = d[tmp.st][tmp.nd];
            EACH(z, ver) {
                ++h;
                s[z.st][z.nd] = cnt;
                d[z.st][z.nd] = h;
            }
        }
        EACH(z, ver) c1[z.st][z.nd] = 1;
    }
    FRN(q, Q) answer(cal(N, P, G[q]));
}
/*
5 5 2
1 0
1 2
3 2
1 3
4 2
2
3 1
1 2

0 0 1 1
0 1 1 1
1 0 0 1
1 1 2 1
2 0 1 0
2 1 3 1
3 0 2 0
3 1 1 0
4 0 2 0
4 1 2 0
----------------------------------------------------------------
From Benq:
    stuff you should look for
        * int overflow, array bounds
        * special cases (n=1?)
        * do smth instead of nothing and stay organized
        * WRITE STUFF DOWN
        * DON'T GET STUCK ON ONE APPROACH
----------------------------------------------------------------
*/

Subtask #1
49.0 / 49.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5076 KB Output is correct
2 Correct 3 ms 5076 KB Output is correct
3 Correct 3 ms 5076 KB Output is correct
4 Correct 4 ms 4948 KB Output is correct
5 Correct 3 ms 4948 KB Output is correct
6 Correct 4 ms 5076 KB Output is correct
7 Correct 3 ms 4948 KB Output is correct
8 Correct 3 ms 5076 KB Output is correct
9 Correct 5 ms 5204 KB Output is correct

Subtask #2
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5076 KB Output is correct
2 Correct 3 ms 5076 KB Output is correct
3 Correct 3 ms 5076 KB Output is correct
4 Correct 4 ms 4948 KB Output is correct
5 Correct 3 ms 4948 KB Output is correct
6 Correct 4 ms 5076 KB Output is correct
7 Correct 3 ms 4948 KB Output is correct
8 Correct 3 ms 5076 KB Output is correct
9 Correct 5 ms 5204 KB Output is correct
10 Correct 3 ms 4948 KB Output is correct
11 Correct 299 ms 6864 KB Output is correct
12 Correct 391 ms 8268 KB Output is correct
13 Correct 45 ms 11924 KB Output is correct
14 Correct 204 ms 15792 KB Output is correct
15 Correct 192 ms 15900 KB Output is correct
16 Correct 1678 ms 12928 KB Output is correct
17 Correct 105 ms 11956 KB Output is correct
18 Correct 122 ms 8140 KB Output is correct
19 Correct 212 ms 15712 KB Output is correct
20 Correct 218 ms 15832 KB Output is correct
21 Correct 700 ms 12856 KB Output is correct
22 Correct 137 ms 11960 KB Output is correct
23 Correct 656 ms 16848 KB Output is correct

Subtask #3
0 / 31.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 5076 KB Output is correct
2 Correct 3 ms 5076 KB Output is correct
3 Correct 3 ms 5076 KB Output is correct
4 Correct 4 ms 4948 KB Output is correct
5 Correct 3 ms 4948 KB Output is correct
6 Correct 4 ms 5076 KB Output is correct
7 Correct 3 ms 4948 KB Output is correct
8 Correct 3 ms 5076 KB Output is correct
9 Correct 5 ms 5204 KB Output is correct
10 Correct 3 ms 4948 KB Output is correct
11 Correct 299 ms 6864 KB Output is correct
12 Correct 391 ms 8268 KB Output is correct
13 Correct 45 ms 11924 KB Output is correct
14 Correct 204 ms 15792 KB Output is correct
15 Correct 192 ms 15900 KB Output is correct
16 Correct 1678 ms 12928 KB Output is correct
17 Correct 105 ms 11956 KB Output is correct
18 Correct 122 ms 8140 KB Output is correct
19 Correct 212 ms 15712 KB Output is correct
20 Correct 218 ms 15832 KB Output is correct
21 Correct 700 ms 12856 KB Output is correct
22 Correct 137 ms 11960 KB Output is correct
23 Correct 656 ms 16848 KB Output is correct
24 Correct 90 ms 4948 KB Output is correct
25 Execution timed out 5054 ms 6864 KB Time limit exceeded
26 Halted 0 ms 0 KB -