제출 #651755

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
651755		ghostwriter	열대 식물원 (Tropical Garden) (IOI11_garden)	C++14	69 / 100	5077 ms	18692 KiB

garden

#include "garden.h"
#include "gardenlib.h"
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#include <debug.h>
#include "grader.cpp"
#else
#define debug(...)
#endif
#define ft front
#define bk back
#define st first
#define nd second
#define ins insert
#define ers erase
#define pb push_back
#define pf push_front
#define _pb pop_back
#define _pf pop_front
#define lb lower_bound
#define ub upper_bound
#define mtp make_tuple
#define bg begin
#define ed end
#define all(x) x.bg(), x.ed()
#define sz(x) (int)x.size()
typedef long long ll; typedef unsigned long long ull;
typedef double db; typedef long double ldb;
typedef pair<int, int> pi; typedef pair<ll, ll> pll;
typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pi> vpi; typedef vector<pll> vpll;
typedef string str;
template<typename T> T gcd(T a, T b) { return (b == 0? a : gcd(b, a % b)); }
template<typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
#define FOR(i, l, r) for (int i = l; i <= r; ++i)
#define FOS(i, r, l) for (int i = r; i >= l; --i)
#define FRN(i, n) for (int i = 0; i < n; ++i)
#define FSN(i, n) for (int i = n - 1; i >= 0; --i)
#define EACH(i, x) for (auto &i : x)
#define WHILE while
#define file "TEST"
mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());
ll rand(ll l, ll r) { return uniform_int_distribution<ll>(l, r)(rd); }
/*
----------------------------------------------------------------
    END OF TEMPLATE
----------------------------------------------------------------
    Tran The Bao - ghostwriter
    Training for VOI23 gold medal
----------------------------------------------------------------
    GOAT
----------------------------------------------------------------
*/
const int MAXN = 15e4 + 5;
int ind[MAXN][2], c[MAXN][2], c1[MAXN][2], s[MAXN][2], d[MAXN][2];
vi adj[MAXN];
vpi e;
pi nxt(pi x) {
    int u = x.st;
    bool stt = x.nd;
    int id = (!stt? 0 : sz(adj[u]) == 1? 0 : 1);
    int nxtv = e[adj[u][id]].st == u? e[adj[u][id]].nd : e[adj[u][id]].st;
    return {nxtv, adj[u][id] == adj[nxtv][0]? 1 : 0};
}
int cal(int N, int P, int x) {
    memset(c, 0, sizeof c);
    int ans = 0;
    FRN(i, N)
    FRN(j, 2) {
        if (ind[i][j]) continue;
        int x1 = x;
        if (x1 > d[i][j]) {
            x1 -= d[i][j];
            x1 %= s[i][j];
            x1 += d[i][j];
        }
        pi cur = {i, j};
        FOR(z, 1, x1) cur = nxt(cur);
        if (cur.st == P && !j) ++ans;
        c[i][j] = 1;
        pi cur1 = nxt({i, j});
        WHILE(!c[cur1.st][cur1.nd]) {
            cur = nxt(cur);
            if (cur.st == P && !cur1.nd) ++ans;
            c[cur1.st][cur1.nd] = 1;
            cur1 = nxt(cur1);
        }
    }
    FRN(i, N)
    FRN(j, 2) {
        if (c[i][j]) continue;
        int x1 = x % s[i][j];
        pi cur = {i, j};
        FOR(z, 1, x1) cur = nxt(cur);
        if (cur.st == P && !j) ++ans;
        c[i][j] = 1;
        pi cur1 = nxt({i, j});
        WHILE(!c[cur1.st][cur1.nd]) {
            cur = nxt(cur);
            if (cur.st == P && !cur1.nd) ++ans;
            c[cur1.st][cur1.nd] = 1;
            cur1 = nxt(cur1);
        }   
    }
    return ans;
}
void count_routes(int N, int M, int P, int R[][2], int Q, int G[]) {
    FRN(i, M) {
        int u = R[i][0], v = R[i][1];
        e.pb({u, v});
        adj[u].pb(i);
        adj[v].pb(i);
    }
    // cerr << '\n';
    FRN(i, N)
    FRN(j, 2) {
        pi tmp1 = nxt({i, j});
        ind[tmp1.st][tmp1.nd] = 1;
        // cerr << i << ' ' << j << ' ' << tmp1.st << ' ' << tmp1.nd << '\n';
        if (c1[i][j]) continue;
        vpi ver;
        pi cur = {i, j};
        WHILE(1) {
            if (!c[cur.st][cur.nd]) ver.pb(cur);
            ++c[cur.st][cur.nd];
            cur = nxt(cur);
            if (c1[cur.st][cur.nd] || c[cur.st][cur.nd] == 2) break;
        }
        reverse(all(ver));
        if (c[ver.ft().st][ver.ft().nd] == 2) {
            int cnt = 0, h = 0;
            EACH(z, ver) if (c[z.st][z.nd] == 2) ++cnt;
            EACH(z, ver) {
                if (c[z.st][z.nd] == 1) ++h;
                s[z.st][z.nd] = cnt;
                d[z.st][z.nd] = h;
            }
        }
        else {
            pi tmp = nxt(ver.ft());
            int cnt = s[tmp.st][tmp.nd], h = d[tmp.st][tmp.nd];
            EACH(z, ver) {
                ++h;
                s[z.st][z.nd] = cnt;
                d[z.st][z.nd] = h;
            }
        }
        EACH(z, ver) c1[z.st][z.nd] = 1;
    }
    // cerr << '\n';
    // FRN(i, N)
    // FRN(j, 2) {
        // debug(i, j, s[i][j], d[i][j]);
    // }
    // debug(cal(N, P, G[0]));
    // return;
    FRN(q, Q) {
        // debug(G[q], cal(N, P, G[q]));
        answer(cal(N, P, G[q]));
    }
}
/*
5 5 2
1 0
1 2
3 2
1 3
4 2
2
3 1
1 2

0 0 1 1
0 1 1 1
1 0 0 1
1 1 2 1
2 0 1 0
2 1 3 1
3 0 2 0
3 1 1 0
4 0 2 0
4 1 2 0
----------------------------------------------------------------
From Benq:
    stuff you should look for
        * int overflow, array bounds
        * special cases (n=1?)
        * do smth instead of nothing and stay organized
        * WRITE STUFF DOWN
        * DON'T GET STUCK ON ONE APPROACH
----------------------------------------------------------------
*/

• Subtask 1: 49 / 49
• Subtask 2: 20 / 20
• Subtask 3: 0 / 31