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/*
Model the system as a graph, where each node (except the first and the last) is an interval between two consecutive
teleport endpoints.
Observation:
The graph will consist of exactly 1 line graph and some (maybe 0) cycles.
The line graph is the the intervals that we will pass through, while the cycles are the intervals we won't pass through.
Observation:
The answer to the problem is K - 1, where K is the number of nodes in the final line graph. So our goal is to maximize
this value.
Observation:
Adding a teleport means that we will interfere at most 2 intervals, i.e nodes. There are 3 possible actions:
1. Add a teleport on an interval. This action adds 1 node to the affected subgraph, and also add 1 cycle with length 1.
2. Add a teleport that connects two different intervals:
a. The intervals are in the same subgraph -> This is not beneficial.
b. The intervals are in different subgraphs -> These subgraphs are merged into a larger subgraph, it has 2 more nodes.
Picture the teleport "hooks" both subgraph.
Algorithm:
* Build the graph
* Identify the line graph and the cycles
* Connect the line graph to the longest cycles first, using action 2b above. Do this as many times as possible.
* If there is still teleports left to be built, alternate action 1 and 2b.
*/
#include<bits/stdc++.h>
using namespace std;
#define INF 2000000002
#define MAXN 1000000
int n, m, nxt[2 * MAXN + 3];
bool visited[2 * MAXN + 3];
vector<pair<int, int> > points;
vector<int> cycleLengths;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
cin >> n >> m;
for (int i = 1; i <= n; i++) {
int w, e;
cin >> w >> e;
points.push_back({w, e});
points.push_back({e, w});
}
memset(nxt, -1, sizeof(nxt));
sort(points.begin(), points.end());
for (int i = 0; i < points.size(); i++) {
auto [x, otherEnd] = points[i];
int idx = upper_bound(points.begin(), points.end(), make_pair(otherEnd, INF)) - points.begin();
nxt[i] = idx;
}
memset(visited, false, sizeof(visited));
// Process the line graph
int numNodesInLineGraph = 0;
int currentNode = 0;
while (currentNode != -1) {
numNodesInLineGraph += 1;
visited[currentNode] = true;
currentNode = nxt[currentNode];
}
// Process the cycles
for (int i = 0; i < 2 * n + 1; i++) {
if (!visited[i]) {
int currentNode = i;
int cycleLength = 0;
while (!visited[currentNode]) {
cycleLength += 1;
visited[currentNode] = true;
currentNode = nxt[currentNode];
}
cycleLengths.push_back(cycleLength);
}
}
sort(cycleLengths.begin(), cycleLengths.end(), greater<int>());
// Connect the line graph with the cycles while possible
for (int i = 0; i < cycleLengths.size() && m > 0; i++, m--) {
numNodesInLineGraph += cycleLengths[i] + 2;
}
// If we can add more teleports..
numNodesInLineGraph += (m/2) * 4 + (m%2);
cout << numNodesInLineGraph - 1 << endl;
}
컴파일 시 표준 에러 (stderr) 메시지
teleporters.cpp: In function 'int main()':
teleporters.cpp:56:21: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::pair<int, int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
56 | for (int i = 0; i < points.size(); i++) {
| ~~^~~~~~~~~~~~~~~
teleporters.cpp:94:21: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
94 | for (int i = 0; i < cycleLengths.size() && m > 0; i++, m--) {
| ~~^~~~~~~~~~~~~~~~~~~~~
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