제출 #646450

#제출 시각아이디문제언어결과실행 시간메모리
646450RichemK개의 묶음 (IZhO14_blocks)C++14
0 / 100
1 ms340 KiB
#include <iostream> #include <stack> #define int long long using namespace std; const int MAX_NOMBRE = 1e5+42, INF = 1e12, MAX_BLOC = 101; struct Elem{ int taille, pos; }; int nbNombre, blocRequis; int nombre[MAX_NOMBRE]; int dp[MAX_NOMBRE][MAX_BLOC]; stack<Elem> s; signed main() { cin >> nbNombre >> blocRequis; for(int i = 0; i < nbNombre; i++) { for(int j = 0; j < blocRequis; j++) dp[i][j] = INF; } for(int cur = 0; cur < nbNombre; cur++) { cin >> nombre[cur]; dp[cur][0] = nombre[cur]; if(cur > 0) dp[cur][0] = max(dp[cur][0], dp[cur-1][0]); } for(int nbBloc = 1; nbBloc < blocRequis; nbBloc++) { while(!s.empty()) s.pop(); s.push({INF, nbBloc-1}); for(int cur = nbBloc; cur < nbNombre; cur++) { int mini = INF; while(s.top().taille <= nombre[cur]) { mini = min(mini, dp[s.top().pos][nbBloc-1] + nombre[cur]); s.pop(); } dp[cur][nbBloc] = min(dp[s.top().pos][nbBloc-1] + nombre[cur], dp[s.top().pos][nbBloc]); dp[cur][nbBloc] = min(dp[cur][nbBloc], mini); s.push({nombre[cur], cur}); } } cout << dp[nbNombre-1][blocRequis-1]; }
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