제출 #646391

#제출 시각아이디문제언어결과실행 시간메모리
646391RichemK개의 묶음 (IZhO14_blocks)C++14
53 / 100
1088 ms8256 KiB
#include <iostream> #define int long long using namespace std; const int MAX_NB = 1e5+42, MAX_BLOC = 101, INF = 1e9; int nbNombre, blocRequis; int nombre[MAX_NB]; int dp[MAX_NB][MAX_BLOC]; signed main() { cin >> nbNombre >> blocRequis; for(int i = 0; i < nbNombre; i++) { for(int j = 0; j < blocRequis; j++) dp[i][j] = INF; } for(int cur = 0; cur < nbNombre; cur++) { cin >> nombre[cur]; dp[cur][0] = nombre[cur]; if(cur > 0) dp[cur][0] = max(dp[cur][0], dp[cur-1][0]); } for(int nbBloc = 1; nbBloc < blocRequis; nbBloc++) { for(int cur = nbBloc; cur < nbNombre; cur++) { int maxi = 0; for(int preced = cur; preced > 0; preced--) { maxi = max(maxi, nombre[preced]); dp[cur][nbBloc] = min(dp[cur][nbBloc], dp[preced-1][nbBloc-1] + maxi); } } } cout << dp[nbNombre-1][blocRequis-1]; }
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