이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <iostream>
using namespace std;
const int MAXN=1e5+5;
int n;
int dostawy[MAXN];
int dp[2][4][4][4];
inline int ore (int a, int b, int c) {
int sol = 0;
if (a == 1 || b == 1 || c == 1) sol++;
if (a == 2 || b == 2 || c == 2) sol++;
if (a == 3 || b == 3 || c == 3) sol++;
return sol;
}
int main() {
int n;
cin >> n;
string input;
cin >> input;
for(int i = 0;i<n;i++){
if(input[i]=='F'){
dostawy[i] = 1;
//s[i] = 1;
}
else if(input[i]=='M'){
dostawy[i] = 2;
//s[i] = 2;
}
else{
dostawy[i] = 3;
//s[i] = 3;
}
}
int now = 0, prev = 1;
for (int k=n-1; k>=0;k--){
for (int a=0; a<=3;a++){
for (int b=0; b<=3;b++){
for (int c=0;c<=3;c++){
int fir = ore(dostawy[k], dostawy[k-1], a) + dp[prev][dostawy[k-1]][b][c];
int sec = ore(dostawy[k], b, c) + dp[prev][b][dostawy[k-1]][a];
dp[now][a][b][c] = max(sec, fir);
}
}
}
swap(now, prev);
}
printf("%d\n", dp[prev][0][0][0]);
return 0;
}
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