제출 #643678

#제출 시각아이디문제언어결과실행 시간메모리
643678ErXiMMiners (IOI07_miners)C++14
0 / 100
24 ms1564 KiB
#include <cstdio> #include <cstdlib> #include <algorithm> #include <iostream> using namespace std; const int MAXN=1e5+5; int n; int dostawy[MAXN]; int dp[2][4][4][4]; inline int ore (int a, int b, int c) { int sol = 0; if (a == 1 || b == 1 || c == 1) sol++; if (a == 2 || b == 2 || c == 2) sol++; if (a == 3 || b == 3 || c == 3) sol++; return sol; } int main() { int n; cin >> n; string input; cin >> input; for(int i = 0;i<n;i++){ if(input[i]=='F'){ dostawy[i] = 1; //s[i] = 1; } else if(input[i]=='M'){ dostawy[i] = 2; //s[i] = 2; } else{ dostawy[i] = 3; //s[i] = 3; } } int now = 0, prev = 1; for (int k=n-1; k>=0;k--){ for (int a=0; a<=3;a++){ for (int b=0; b<=3;b++){ for (int c=0;c<=3;c++){ int fir = ore(dostawy[k], dostawy[k-1], a) + dp[prev][dostawy[k-1]][b][c]; int sec = ore(dostawy[k], b, c) + dp[prev][b][dostawy[k-1]][a]; dp[now][a][b][c] = max(sec, fir); } } } swap(now, prev); } printf("%d\n", dp[prev][0][0][0]); return 0; }
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