이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define db double
#define pairll pair<ll,ll>
#define lpairll pair<ll,pairll>
#define repp(i,a,b) for (ll i = a; i <= b; i++)
#define repz(i,a,b) for (ll i = a; i < b; i++)
#define repm(i,a,b) for (ll i = a; i >= b; i--)
#define fr first
#define sc second
#define mp make_pair
#define pb push_back
const ll N = 2e5+5, MOD = 1e9+7, LOG = 20;
ll tc = 1, n, m, ar[N], br[N], used[N];
ll x, y, k, cur = 0;
string s, s1, s2, ye = "YES", no = "NO";
ll ord[N], root, nx[N][LOG+5], dlm[N], smol[N];
vector<ll> ed[N];
void buildord(ll idx){
for (auto i : ed[idx]){
dlm[i] = dlm[idx]+1;
buildord(i);
}
cur++;
ord[idx] = cur;
}
void buildlift(){
nx[root][0] = 0;
repp(bt,1,LOG){
repp(i,1,n){
nx[i][bt] = nx[nx[i][bt-1]][bt-1];
}
}
}
void input(){
cin >> n >> m;
repp(i,1,n){
cin >> ar[i];
if (ar[i] == 0){
if (root != 0) assert(0);
root = i;
}
else{
ed[ar[i]].pb(i);
nx[i][0] = ar[i];
}
}
}
void buildsmol(ll idx){
smol[idx] = idx;
for (auto i : ed[idx]){
buildsmol(i);
smol[idx] = min(smol[idx],smol[i]);
}
//cout << idx << " " << smol[idx] << endl;
}
bool cmp (ll a, ll b){
return (smol[a] < smol[b]);
}
void solve(){
buildsmol(root);
repp(i,1,n){
sort(ed[i].begin(),ed[i].end(),cmp);
}
buildord(root);
buildlift();
priority_queue<pairll, vector<pairll>, greater<pairll> > pq;
repp(i,1,n){
pq.push(mp(ord[i],i));
}
while(m--){
cin >> x >> y;
if (x == 1){
ll lst;
while(y--){
pairll a = pq.top();
pq.pop();
used[a.sc] = 1;
lst = a.sc;
}
cout << lst << "\n";
}
else if(x == 2){
ll dis = 0, ori = y;
repm(bt,LOG,0){
if (used[nx[y][bt]]){
dis += (1<<bt);
y = nx[y][bt];
}
}
used[y] = 0;
pq.push(mp(ord[y],y));
cout << dis << "\n";
}
}
}
int main(){
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
//cin >> tc;
while(tc--){
input();
solve();
}
}
컴파일 시 표준 에러 (stderr) 메시지
ballmachine.cpp: In function 'void solve()':
ballmachine.cpp:94:19: warning: unused variable 'ori' [-Wunused-variable]
94 | ll dis = 0, ori = y;
| ^~~
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