제출 #638852

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
638852		ShirleyM	보물 찾기 (CEOI13_treasure2)	C++17	100 / 100	1 ms	468 KiB

treasure

#include <bits/stdc++.h>
#include "treasure.h"
 
using namespace std;
 
typedef long long ll;
 
const int N_MAX = 100;
 
int N;
 
bool found[N_MAX + 2][N_MAX + 2];
 
int UL[N_MAX + 2][N_MAX + 2];
int UR[N_MAX + 2][N_MAX + 2];
int DL[N_MAX + 2][N_MAX + 2];
int DR[N_MAX + 2][N_MAX + 2];
 
void findTreasure(int N) {
    int mid = (N + 1) / 2;
    // Compute sum of cheaper corner
    for (int i = 1; i <= mid; i++) {
        for (int j = 1; j <= mid; j++) {
            DR[i][j] = countTreasure(i, j, N, N);
        }
    }
    for (int i = 1; i <= mid; i++) {
        for (int j = mid; j < N; j++) {
            DL[i][j] = countTreasure(i, 1, N, j);
        }
    }
    for (int i = 1; i <= mid; i++) {
        DL[i][N] = DR[i][1];
    }
    for (int i = mid; i < N; i++) {
        for (int j = 1; j <= mid; j++) {
            UR[i][j] = countTreasure(1, j, i, N);
        }
    }
    for (int j = 1; j <= mid; j++) {
        UR[N][j] = DR[1][j];
    }
    for (int i = mid; i < N; i++) {
        for (int j = mid; j < N; j++) {
            UL[i][j] = countTreasure(1, 1, i, j);
        }
    }
    for (int i = mid; i <= N; i++) {
        UL[i][N] = UR[i][1];
    }
    for (int j = mid; j <= N; j++) {
        UL[N][j] = DL[1][j];
    }
    // Compute sum of upper-left corner
    for (int i = 1; i <= mid - 1; i++) {
        for (int j = mid; j <= N; j++) {
            UL[i][j] = DL[1][j] - DL[i + 1][j];
        }
    }
    for (int i = mid; i <= N; i++) {
        for (int j = 1; j <= mid - 1; j++) {
            UL[i][j] = UR[i][1] - UR[i][j + 1];
        }
    }
    for (int i = 1; i <= mid - 1; i++) {
        for (int j = 1; j <= mid - 1; j++) {
            UL[i][j] = UL[i][N] + UL[N][j] + DR[i + 1][j + 1] - DR[1][1];
        }
    }
    for (int i = 1; i <= N; i++) {
        for (int j = 1; j <= N; j++) {
            found[i][j] = UL[i][j] - UL[i - 1][j] - UL[i][j - 1] + UL[i - 1][j - 1];
        }
    }
    for (int i = 1; i <= N; i++) {
        for (int j = 1; j <= N; j++) {
            if (found[i][j] == true) {
                Report(i, j);
            }
        }
    }
}

• Subtask 1: 100 / 100