oj.uz

답안 #638234

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
638234 2022-09-05T04:48:54 Z tabr 늑대인간 (IOI18_werewolf) C++17
15 / 100
 4000 ms 74372 KB 
#include <bits/stdc++.h>
using namespace std;
#ifdef tabr
#include "library/debug.cpp"
#else
#define debug(...)
#endif

template <typename T>
struct forest {
    struct edge {
        int from;
        int to;
        T cost;
        edge(int _from, int _to, T _cost) : from(_from), to(_to), cost(_cost) {}
    };

    int n;
    vector<edge> edges;
    vector<vector<int>> g;
    vector<int> pv;
    vector<int> pe;
    vector<int> depth;
    vector<int> root;
    vector<int> sz;
    vector<int> order;
    vector<int> beg;
    vector<int> end;
    vector<T> dist;

    forest(int _n) : n(_n) {
        g = vector<vector<int>>(n);
        init();
    }

    void init() {
        pv = vector<int>(n, -1);
        pe = vector<int>(n, -1);
        depth = vector<int>(n, -1);
        root = vector<int>(n, -1);
        sz = vector<int>(n, 0);
        order = vector<int>();
        beg = vector<int>(n, -1);
        end = vector<int>(n, -1);
        dist = vector<T>(n, 0);
    }

    int add(int from, int to, T cost = 1) {
        int id = (int) edges.size();
        g[from].emplace_back(id);
        g[to].emplace_back(id);
        edges.emplace_back(from, to, cost);
        return id;
    }

    void do_dfs(int v) {
        beg[v] = (int) order.size();
        order.emplace_back(v);
        sz[v] = 1;
        for (int id : g[v]) {
            if (id == pe[v]) {
                continue;
            }
            edge e = edges[id];
            int to = e.from ^ e.to ^ v;
            pv[to] = v;
            pe[to] = id;
            depth[to] = depth[v] + 1;
            root[to] = (root[v] != -1 ? root[v] : to);
            dist[to] = dist[v] + e.cost;
            do_dfs(to);
            sz[v] += sz[to];
        }
        end[v] = (int) order.size();
    }

    void dfs(int v) {
        pv[v] = -1;
        pe[v] = -1;
        depth[v] = 0;
        root[v] = v;
        order.clear();
        dist[v] = 0;
        do_dfs(v);
    }

    void dfs_all() {
        init();
        for (int v = 0; v < n; v++) {
            if (depth[v] == -1) {
                dfs(v);
            }
        }
    }

    int h = -1;
    vector<vector<int>> p;

    inline void build_lca() {
        int max_depth = *max_element(depth.begin(), depth.end());
        h = 1;
        while ((1 << h) <= max_depth) {
            h++;
        }
        p = vector<vector<int>>(h, vector<int>(n));
        p[0] = pv;
        for (int i = 1; i < h; i++) {
            for (int j = 0; j < n; j++) {
                p[i][j] = (p[i - 1][j] == -1 ? -1 : p[i - 1][p[i - 1][j]]);
            }
        }
    }

    inline bool anc(int x, int y) {  // return x is y's ancestor or not
        return (beg[x] <= beg[y] && end[y] <= end[x]);
    }

    inline int go_up(int x, int up) {
        assert(h != -1);
        up = min(up, (1 << h) - 1);
        for (int i = h - 1; i >= 0; i--) {
            if (up & (1 << i)) {
                x = p[i][x];
                if (x == -1) {
                    break;
                }
            }
        }
        return x;
    }

    inline int lca(int x, int y) {
        assert(h != -1);
        if (anc(x, y)) {
            return x;
        }
        if (anc(y, x)) {
            return y;
        }
        for (int i = h - 1; i >= 0; i--) {
            if (p[i][x] != -1 && !anc(p[i][x], y)) {
                x = p[i][x];
            }
        }
        return p[0][x];
    }

    inline T distance(int x, int y) {
        return dist[x] + dist[y] - 2 * dist[lca(x, y)];
    }
};

struct dsu {
    vector<int> p;
    vector<int> sz;
    int n;

    dsu(int _n) : n(_n) {
        p = vector<int>(n);
        iota(p.begin(), p.end(), 0);
        sz = vector<int>(n, 1);
    }

    inline int get(int x) {
        if (p[x] == x) {
            return x;
        } else {
            return p[x] = get(p[x]);
        }
    }

    inline bool unite(int x, int y) {
        x = get(x);
        y = get(y);
        if (x == y) {
            return false;
        }
        p[x] = y;
        sz[y] += sz[x];
        return true;
    }

    inline bool same(int x, int y) {
        return (get(x) == get(y));
    }

    inline int size(int x) {
        return sz[get(x)];
    }

    inline bool root(int x) {
        return (x == get(x));
    }
};

vector<int> check_validity(int n, vector<int> x, vector<int> y, vector<int> s, vector<int> e, vector<int> l, vector<int> r) {
    int m = (int) x.size();
    int q = (int) s.size();
    vector<vector<int>> g(n);
    for (int i = 0; i < m; i++) {
        g[x[i]].emplace_back(y[i]);
        g[y[i]].emplace_back(x[i]);
    }
    forest<int> g0(n), g1(n);
    dsu uf(n);
    for (int i = n - 1; i >= 0; i--) {
        for (int j : g[i]) {
            if (j > i && !uf.same(i, j)) {
                g0.add(i, uf.get(j));
                uf.unite(j, i);
            }
        }
    }
    g0.dfs(0);
    g0.build_lca();
    uf = dsu(n);
    for (int i = 0; i < n; i++) {
        for (int j : g[i]) {
            if (i > j && !uf.same(i, j)) {
                g1.add(i, uf.get(j));
                uf.unite(j, i);
            }
        }
    }
    g1.dfs(n - 1);
    g1.build_lca();
    vector<int> res(q);
    for (int i = 0; i < q; i++) {
        for (int j = l[i]; j <= r[i]; j++) {
            if (g0.lca(j, s[i]) >= l[i] && g1.lca(j, e[i]) <= r[i]) {
                res[i] = 1;
                break;
            }
        }
    }
    return res;
}

#ifdef tabr
int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    debug(check_validity(6, {5, 1, 1, 3, 3, 5}, {1, 2, 3, 4, 0, 2}, {4, 4, 5}, {2, 2, 4}, {1, 2, 3}, {2, 2, 4}));
    return 0;
}
#endif

Subtask #1
7.0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 340 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 0 ms 212 KB Output is correct

Subtask #2
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 340 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 78 ms 1552 KB Output is correct
11 Correct 119 ms 1516 KB Output is correct
12 Correct 124 ms 1372 KB Output is correct
13 Correct 42 ms 1680 KB Output is correct
14 Correct 28 ms 1628 KB Output is correct
15 Correct 424 ms 1588 KB Output is correct

Subtask #3
0 / 34.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 4061 ms 74372 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #4
0 / 51.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 340 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 78 ms 1552 KB Output is correct
11 Correct 119 ms 1516 KB Output is correct
12 Correct 124 ms 1372 KB Output is correct
13 Correct 42 ms 1680 KB Output is correct
14 Correct 28 ms 1628 KB Output is correct
15 Correct 424 ms 1588 KB Output is correct
16 Execution timed out 4061 ms 74372 KB Time limit exceeded
17 Halted 0 ms 0 KB -