이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "aliens.h"
#include<bits/stdc++.h>
using namespace std;
bool cmp(pair<int,int> a,pair<int,int> b)
{
if(a.first==b.first)
return a.second>b.second;
return a.first<b.first;
}
bool inters(pair<int,int> a,pair<int,int> b)
{
if(a.first<=b.first && a.second>=b.second)
return true;
return false;
}
long long take_photos(int n, int m, int k, std::vector<int> r, std::vector<int> c) {
if(n<=50 && m<=100 && k==n) //First Subtask
{
int sol = 0;
vector<vector<int> > matrix;
matrix.resize(m);
for(int i = 0;i<m;i++)
matrix[i].resize(m);
for(int i=0;i<m;i++)
for(int j=0;j<m;j++)
matrix[i][j] = 0;
for(int i = 0;i<n;i++)
{
if(matrix[r[i]][c[i]]) continue;
int m = min(r[i],c[i]);
int M = max(r[i],c[i]);
for(int j = m;j<=M;j++)
for(int t = m;t<=M;t++)
matrix[j][t] = 1;
}
for(int i = 0;i<m;i++)
for(int j=0;j<m;j++)
sol+=matrix[i][j];
return sol;
}
bool flag = true;
for(int i = 0;i<n;i++)
if(r[i]!=c[i])
{
flag = false;
break;
}
if(n<=500 && m<=1000 && flag)
{
vector<pair<int,int> > obj;
for(int i = 0;i<n;i++)
obj.emplace_back(r[i],c[i]);
sort(obj.begin(),obj.end());
vector<vector<int> > dp;
dp.resize(n+1);
for(int i=0;i<=n;i++)
{
dp[i].resize(k+1);
for(int j=0;j<=k;j++)
dp[i][j] = 1000000000;
}
dp[0][0] = 0;
for(int i = 0;i<n;i++)
{
for(int j = 0;j<=i;j++) {
for (int t = 1; t <= k; t++) {
int area = (obj[i].first - obj[j].first + 1) * (obj[i].second - obj[j].second + 1);
dp[i+1][t] = min(dp[i+1][t], dp[j][t-1] + area);
}
}
}
int sol = INT_MAX;
for(int j=1;j<=k;j++)
sol=min(sol,dp[n][j]);
return sol;
}
else
if(n<=500 && m<=1000)
{
vector<pair<int,int> > obj;
vector<pair<int,int> > aux;
for(int i = 0;i<n;i++)
aux.emplace_back(min(r[i],c[i]),max(r[i],c[i]));
sort(aux.begin(),aux.end(),cmp);
obj.emplace_back(-1,-1);
for(auto it:aux)
{
if(!inters(obj.back(),it))
obj.push_back(it);
}
n = obj.size();
vector<vector<int> > dp;
dp.resize(n+1);
for(int i=0;i<=n;i++)
{
dp[i].resize(k+1);
for(int j=0;j<=k;j++)
dp[i][j] = 1000000000;
}
dp[0][0] = 0;
for(int i = 1;i<n;i++)
{
for(int j = 1;j<=i;j++)
{
for(int t=1;t<=k;t++)
{
dp[i][t] = min(dp[i][t],dp[j-1][t-1] + (obj[i].second-obj[j].first+1)*(obj[i].second-obj[j].first+1) - max(0,obj[j-1].second-obj[j].first+1)*max(0,obj[j-1].second-obj[j].first+1));
}
}
}
int sol = INT_MAX;
for(int j=1;j<=k;j++)
sol=min(sol,dp[n-1][j]);
return sol;
}
return 0;
}
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