답안 #63439 :: oj.uz

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
63439	2018-08-01T19:42:41 Z	Benq	Nuclearia (CEOI15_nuclearia)	C++11	19 / 100	1000 ms	331376 KB

nuclearia

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

struct bad {
    int W,H;
    ll dat[2500000];
    void init(int _W, int _H) {
        W = _W, H = _H;
        // F0R(i,2500000) dat[i] = 0;
        memset(dat,0,sizeof dat);
    }
    ll get(int a, int b) { 
        assert(0 <= a && a < W && 0 <= b && b < H);
        return dat[H*a+b]; 
    }
    void ad(int a, int b, ll val) { 
        assert(0 <= a && a < W && 0 <= b && b < H);
        dat[H*a+b] += val; 
    }
};

vector<vl> make(int a, int b) {
    vector<vl> v(a); F0R(i,a) v[i].resize(b);
    return v;
}

struct cum {
    bad L, up, down;
    int W,H;
    void init(int _W, int _H) { 
        W = _W, H = _H;
        L.init(W,H), up.init(W,H), down.init(W,H); 
    }
    void prop() {
        F0R(i,W) {
            F0R(j,H) {
                L.ad(i,j,down.get(i,j)+up.get(i,j));
                if (i != W-1) {
                    up.ad(i+1,min(H-1,j+1),up.get(i,j));
                    if (j) down.ad(i+1,j-1,down.get(i,j));
                }
            }
        }
        F0R(i,W) F0Rd(j,H-1) L.ad(i,j,L.get(i,j+1));
    }
};

cum c, cX;
int W,H,N;
vector<vl> res, ans;
vector<array<int,4>> todo;

pi trans(pi x) {
    return {H-1-x.s,x.f};
}

void prin(vector<vl> v) {
    F0R(i,sz(v)) {
        F0R(j,sz(v[i])) cout << v[i][j] << " ";
        cout << "\n";
    }
    cout << "----\n";
}

void rot() {
    vector<vl> RES = make(H,W);
    F0R(i,W) F0R(j,H) {
        pi x = trans({i,j});
        RES[x.f][x.s] = res[i][j];
    }
    F0R(i,sz(todo)) {
        pi x = trans({todo[i][0],todo[i][1]});
        todo[i][0] = x.f, todo[i][1] = x.s;
    }
    //prin(res);
    //prin(RES);
    swap(res,RES); swap(W,H);
}

void prop() {
    c.prop(), cX.prop();
    assert(W == c.W && H == c.H);
    F0R(i,W) F0R(j,H) res[i][j] += c.L.get(i,j)+cX.L.get(i,j)*i;
}

void process(array<int,4> a) {
    // cout << "TT\n";
    assert(0 <= a[0] && a[0] < W && 0 <= a[1] && a[1] < H);
    int mul = a[2]/a[3];
    ll z = a[2]+(ll)a[0]*a[3];
    if (a[0]+1 < W) {
        c.up.ad(a[0]+1,a[1],z);
        cX.up.ad(a[0]+1,a[1],-a[3]);
    }
    if (a[0]+mul+1 < W) {
        c.up.ad(a[0]+1+mul,min(a[1]+mul,H-1),-z);
        cX.up.ad(a[0]+1+mul,min(a[1]+mul,H-1),a[3]);
    }
    if (a[0]+1 < W && a[1]-2 >= 0) {
        c.down.ad(a[0]+1,a[1]-2,-z);
        cX.down.ad(a[0]+1,a[1]-2,a[3]);
    }
    if (a[0]+1+mul < W && a[1]-2-mul >= 0) {
        c.down.ad(a[0]+1+mul,a[1]-2-mul,z);
        cX.down.ad(a[0]+1+mul,a[1]-2-mul,-a[3]);
    }
}

void solve() {
    c.init(W,H), cX.init(W,H);
    for (auto a: todo) process(a);
    prop();
}

ll query(int x1, int x2, int y1, int y2) {
    return ans[x2][y2]-ans[x1-1][y2]-ans[x2][y1-1]+ans[x1-1][y1-1];
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> W >> H >> N;
    res = make(W,H);
    F0R(i,N) {
        int x,y,a,b; // int x = rand() % W+1,y = rand() % H+1,a = rand() % 500+1,b = rand() % 50+1; 
        cin >> x >> y >> a >> b; 
        x--, y--;
        res[x][y] += a;
        todo.pb({x,y,a,b});
    }
    F0R(i,4) {
        solve();
        rot();
    }
    /*F0R(i,W) {
        F0R(j,H) cout << res[i][j] << " ";
        cout << "\n";
    }
    exit(0);*/
    ans = make(W+1,H+1);
    FOR(i,1,W+1) {
        FOR(j,1,H+1) {
            ans[i][j] = res[i-1][j-1]+ans[i-1][j]+ans[i][j-1]-ans[i-1][j-1];
        }
    }
    int Q; cin >> Q;
    F0R(i,Q) {
        int x1,y1,x2,y2; cin >> x1 >> y1 >> x2 >> y2;
        cout << (ll)round((ld)query(x1,x2,y1,y2)/(x2-x1+1)/(y2-y1+1)) << "\n";
    }
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

Subtask #1
0 / 3.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1088 ms	297200 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #2
0 / 2.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1085 ms	297200 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #3
3.0 / 3.0

#	결과	실행 시간	메모리	Grader output
1	Correct	819 ms	297200 KB	Output is correct
2	Correct	309 ms	297200 KB	Output is correct

Subtask #4
2.0 / 2.0

#	결과	실행 시간	메모리	Grader output
1	Correct	738 ms	297200 KB	Output is correct
2	Correct	248 ms	297200 KB	Output is correct

Subtask #5
0 / 6.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1099 ms	331376 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #6
4.0 / 4.0

#	결과	실행 시간	메모리	Grader output
1	Correct	800 ms	331376 KB	Output is correct
2	Correct	294 ms	331376 KB	Output is correct

Subtask #7
6.0 / 6.0

#	결과	실행 시간	메모리	Grader output
1	Correct	756 ms	331376 KB	Output is correct
2	Correct	324 ms	331376 KB	Output is correct

Subtask #8
4.0 / 4.0

#	결과	실행 시간	메모리	Grader output
1	Correct	757 ms	331376 KB	Output is correct
2	Correct	274 ms	331376 KB	Output is correct

Subtask #9
0 / 15.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1098 ms	331376 KB	Time limit exceeded

Subtask #10
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1112 ms	331376 KB	Time limit exceeded

Subtask #11
0 / 15.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1086 ms	331376 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #12
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1097 ms	331376 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #13
0 / 12.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1065 ms	331376 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #14
0 / 8.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1010 ms	331376 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

답안 #63439

Compilation message