제출 #633650

#제출 시각아이디문제언어결과실행 시간메모리
633650Cyber_WolfMiners (IOI07_miners)C++14
9 / 100
371 ms52436 KiB
//Contest: IOI'07 D2 P1 //Problem: Miners //Link: https://oj.uz/problem/view/IOI07_miners #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #pragma GCC optimize("Ofast") using namespace std; using namespace __gnu_pbds; #define lg long long #define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> #define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); #define error(args...) { string _s = #args; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, args); #define endl \n #define lbound(x, y) lower_bound(x.begin(), x.end(), y) #define ubound(x, y) upper_bound(x.begin(), x.end(), y) #define sortasc(v) sort(v.begin(), v.end()) #define sortdesc(v) sort(v.rbegin(), v.rend()) #define custom_array(a,l, r) int _##a[r-l+1]; int*a=_##a-l; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const lg MOD = 1e9+7, N = 5e4+5, M = 1e7+1, SZ = 1e3+1; /* bitset<N> primes; lg pwrs[N], inv[N]; lg fast_power(lg n, lg k) { if(!k) return 1; if(k&1) return (fast_power(n, k-1)*n)%MOD; lg x = fast_power(n, k/2)%MOD; return (x*x)%MOD; } void sieve() { primes.set(); primes[0] = primes[1] = 0; for(lg i = 2; i < N; i++) { if(!primes[i]) continue; for(lg j = i*i; j < N; j += i) { primes[j] = 0; } } return; } struct matrix { vector<vector<lg>> con = vector<vector<lg>> (SZ, vector<lg> (SZ)); matrix operator *(const matrix& a) { matrix product; for(int i = 0; i < (lg)con.size(); i++) { for(int j = 0; j < (lg)a.con[0].size(); j++) { for(int k = 0; k < (lg)a.con.size(); k++) { product.con[i][j] = (product.con[i][j]+(con[i][k]*a.con[k][j])%MOD)%MOD; } } } return product; } }; void preprocess(lg x) { inv[2e5] = fast_power(x, MOD-2); for(int i = 2e5-1; i > 1; i--) { inv[i] = (inv[i+1]*i)%MOD; } pwrs[0] = 1; for(int i = 1; i <= 2e5; i++) { pwrs[i] = (pwrs[i]*i)%MOD; } return; } */ lg dp[N][4][4][4]; lg n; string s; vector<lg> v(N); lg solve(lg idx, lg x, lg y, lg z) { if(idx == n) { return 0; } auto &ret = dp[idx][x][y][z]; if(~ret) return ret; set<lg> se1; if(v[idx] != 3) se1.insert(v[idx]); if(x != 3) se1.insert(x); if(y != 3) se1.insert(y); set<lg> se2; se2.insert(v[idx]); lg cur = idx; vector<lg> vis(3); lg t = 0; while(cur-- && t != 2) { if(!vis[0] && x == v[cur]) { vis[0] = true; } else if(!vis[1] && y == v[cur]) { vis[1] = true; } else if(!vis[2] && z == v[cur]) { vis[2] = true; } else{ se2.insert(v[cur]); t++; } } lg ch1 = solve(idx+1, v[idx], x, y)+se1.size(); lg ch2 = solve(idx+1, x, y, z)+se2.size(); return ret = max(ch1, ch2); } int main() { fastio; cin >> n >> s; for(int i = 0; i < n; i++) { if(s[i] == 'M') v[i] = 1; if(s[i] == 'B') v[i] = 2; for(int j = 0; j < 4; j++) { for(int k = 0; k < 4; k++) { for(int z = 0; z < 4; z++) { dp[i][j][k][z] = -1; } } } } cout << solve(0, 3, 3, 3)-1 << '\n'; return 0; }
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