제출 #633346

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
633346		codr0	Dabbeh (INOI20_dabbeh)	C++14	0 / 100	820 ms	56520 KiB

Main

// Code by Parsa Eslami

#include <bits/stdc++.h>
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>

#define FOR(i,a,b) for(int i=a;i<=b;i++)
#define FORR(i,a,b) for(int i=a;i>=b;i--)
#define maxm(a,b) a=max(a,b)
#define minm(a,b) a=min(a,b)
#define bit(i,j) ((j>>i)&1)
#define F first
#define S second
#define dmid int mid=(r+l)/2
#define lc 2*id
#define rc 2*id+1
#define err(x) cerr<<#x<<"="<<x<<'\n'
#define pb push_back
#define SZ(x) (int)x.size()
#define all(x) x.begin(),x.end()

using namespace std;
const int md=1000696969;
const int base=31;
const int N=3e5+4;
const int lg=20;
int PW[N],inv[N];
int hsh[N];
int nxt[lg][N];
int big[lg][N];

	inline int mkey(int a,int b){ int rt=a+b; if(rt>=md) rt-=md; return rt;}

	int pw(int a,int b){
		int rt=1;
		while(b){
			if(b&1) rt=1LL*rt*a%md;
			a=1LL*a*a%md;
			b/=2;
		}
		return rt;
	}

	int h(int l,int r){
		int rt=mkey(hsh[r],md-hsh[l-1]);
		rt=1LL*rt*inv[l-1]%md;
		return rt;
	}

	int32_t main(){
	iostream::sync_with_stdio(0); cin.tie(0);

	PW[0]=1; FOR(i,1,N-1) PW[i]=1LL*PW[i-1]*base%md;
	inv[N-1]=pw(PW[N-1],md-2); FORR(i,N-2,0) inv[i]=1LL*inv[i+1]*base%md;
	int n,m; cin>>n>>m;
	vector<pii> vc;
	FOR(i,1,n){
		string x; cin>>x;
		int HSH=0;
		FOR(j,0,SZ(x)-1){
			HSH=mkey(HSH,1LL*(x[j]-'a'+1)*PW[j]%md);
			vc.pb({HSH,j+1});
		}
	}
	sort(all(vc));
	string s; cin>>s;
	s='#'+s;
	FOR(i,1,SZ(s)-1){
		hsh[i]=mkey(hsh[i-1],1LL*PW[i-1]*(s[i]-'a'+1)%md);
	}
	vector<pii> st;
	FORR(i,SZ(s)-2,0){
		int l=i,r=SZ(s);
		while(r-l>1){
			dmid;
			int HSH=h(i+1,mid);
			pii ty={HSH,mid-i};
			auto it=lower_bound(all(vc),ty);
			if(it!=vc.end()&&(*it)==ty) l=mid;
			else r=mid;
		}
		int L=-1,R=SZ(st);
		while(R-L>1){
			int mid=(R+L)/2;
			if(st[mid].S<=l) R=mid;
			else L=mid;
		}
		if(R==SZ(st)||st[R].F<=l) nxt[0][i]=l;
		else nxt[0][i]=st[R].S;
		while(!st.empty()&&st.back().F<=l) st.pop_back();
		st.pb({l,i});
		big[0][i]=l;
	}
	nxt[0][SZ(s)-1]=SZ(s)-1;
	FOR(j,1,lg-1) FOR(i,0,SZ(s)-1) nxt[j][i]=nxt[j-1][nxt[j-1][i]];
	FOR(j,1,lg-1) FOR(i,0,SZ(s)-1) big[j][i]=big[j-1][nxt[j-1][i]];
//	FOR(i,0,SZ(s)-1) cout<<nxt[0][i]<<" ";
//	cout<<'\n';
	while(m--){
		int l,r; cin>>l>>r;
		int ans=0;
		FORR(j,lg-1,0) if(nxt[j][l]<r&&big[j][l]<r){
	//		cout<<l<<" "<<j<<" "<<nxt[j][l]<<'\n';
			l=nxt[j][l];
			ans+=(1<<j);
		}
		ans++;
		if(ans>SZ(s)) ans=-1;
		cout<<ans<<'\n';
	}

	return 0;
	}

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