이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define fi first
#define se second
#define ll long long
#define ld long double
#define sz(x) ((int)(x).size())
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define mpp make_pair
#define ve vector
using namespace std;
using namespace __gnu_pbds;
template<class T> using oset = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
const ll inf = 1e18; const int iinf = 1e9;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
template <typename T> inline bool chmin(T& a, T b) { return (a > b ? a = b, 1 : 0); }
template <typename T> inline bool chmax(T& a, T b) { return (a < b ? a = b, 1 : 0); }
const int N = 5e4 + 10;
int p[N], rnk[N];
inline void build(int n) { for (int i = 0; i < n; ++i) p[i] = i, rnk[i] = 1; }
inline int par(int v) { if (p[v] == v) { return v; } return p[v] = par(p[v]); }
inline bool uni(int a, int b) {
a = par(a), b = par(b);
if (a == b) return 0;
if (rnk[a] > rnk[b]) swap(a, b);
p[a] = b, rnk[b] += rnk[a]; return 1;
}
inline void solve() {
int n, m;
cin >> n >> m;
ve<array<int,3>> e(m);
for (auto &[v, u, w] : e) cin >> v >> u >> w, --v, --u;
int q;
cin >> q;
ve<array<int,3>> ar(q);
for (auto &[t, a, b] : ar) {
cin >> t >> a >> b;
--a;
}
set<array<int,4>> E; int P = 0;
for (auto &[v, u, w] : e) E.insert({w, v, u, P++});
ve<int> res(q, -1);
const int b = 400;
ve<int> used(n);
ve<ve<int>> gr(n);
ve<int> changed(m);
for (int l = 0; l < q; l += b) {
int r = min(q - 1, l + b - 1);
for (int i = l; i <= r; ++i) {
if (ar[i][0] == 1) {
changed[ar[i][1]] = 1;
}
}
ve<array<int,3>> edges;
edges.reserve(m);
for (auto &[w, v, u, id] : E) {
if (changed[id]) continue;
edges.pb({w, v, u});
}
for (int i = l; i <= r; ++i) {
if (ar[i][0] == 1) {
changed[ar[i][1]] = 0;
}
}
ve<pair<array<int,3>,ve<array<int,3>>>> que;
que.reserve(r - l + 1);
for (int i = l; i <= r; ++i) {
if (ar[i][0] == 1) {
int id = ar[i][1];
int x = ar[i][2];
E.erase({e[id][2], e[id][0], e[id][1], id});
e[id][2] = x;
E.insert({e[id][2], e[id][0], e[id][1], id});
}
else {
int s = ar[i][1], d = ar[i][2];
que.pb({{-d,s,i}, {}});
for (int j = l; j <= r; ++j) {
if (ar[j][0] == 2) continue;
int id = ar[j][1]; int w = e[id][2];
if (w >= d) que.back().se.pb({e[id][0], e[id][1], w});
}
}
}
build(n);
sort(all(que));
int p = sz(edges) - 1;
for (auto &[_, vec] : que) {
auto &[d, s, id] = _; d *= -1;
while (~p && edges[p][0] >= d) {
auto &[w, v, u] = edges[p];
uni(v, u);
--p;
}
for (auto &[v, u, w] : vec) {
gr[par(v)].pb(par(u));
gr[par(u)].pb(par(v));
}
int ans = 0;
function<void(int)> dfs = [&gr,&used,&dfs,&ans](int v) {
used[v] = 1; ans += rnk[v];
for (auto &to : gr[v]) {
if (used[to]) continue;
dfs(to);
}
};
dfs(par(s));
res[id] = ans;
used[par(s)] = 0;
for (auto &[v, u, w] : vec) {
gr[par(u)].clear();
gr[par(v)].clear();
used[par(v)] = used[par(u)] = 0;
}
}
}
for (int i = 0; i < q; ++i) if (~res[i]) cout << res[i] << '\n';
}
signed main() {
ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
int q = 1; // cin >> q;
while (q--) solve();
cerr << fixed << setprecision(3) << "Time execution: " << (double)clock() / CLOCKS_PER_SEC << endl;
}
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