Submission #632851

#	Time	Username	Problem	Language	Result	Execution time	Memory
632851		LeticiaFCS	Zemljište (COCI22_zemljiste)	C++17	70 / 70	478 ms	4812 KiB

Main

#include "bits/stdc++.h"
#define st first
#define nd second
using lint = int64_t;
constexpr int MOD = int(1e9) + 7;
constexpr int INF = 0x3f3f3f3f;
constexpr int NINF = 0xcfcfcfcf;
constexpr lint LINF = 0x3f3f3f3f3f3f3f3f;
const long double PI = acosl(-1.0);
// Returns -1 if a < b, 0 if a = b and 1 if a > b.
int cmp_double(double a, double b = 0, double eps = 1e-9) {
	return a + eps > b ? b + eps > a ? 0 : 1 : -1;
}
using namespace std;


int r, s;
lint a, b;

vector<vector<lint>> prefix;

lint getSum(int l, int r, int sr, int er){
	if(r < l || er < sr) return 0;
	lint ans = prefix[r][er];
	ans -= prefix[l-1][er] + prefix[r][sr-1];
	ans += prefix[l-1][sr-1];
	return ans;
}

int main() {
	cin.tie(nullptr)->sync_with_stdio(false);
	cin>>r>>s>>a>>b;
	if(a > b) swap(a, b);
	lint ans = LINF;
	prefix = vector<vector<lint>>(r+2, vector<lint>(s+2));
	for(int i=1; i<=r; i++)
		for(int j=1; j<=s; j++){
			cin>>prefix[i][j];
			prefix[i][j] += prefix[i-1][j] + prefix[i][j-1];
			prefix[i][j] -= prefix[i-1][j-1];
		}
	//cout<<"\ta "<<a<<" b "<<b<<"\n"; return 0;
	for(int sr=1; sr<=s; sr++)
		for(int er=sr; er<=s; er++){
			int left=1;
			lint cur = 0;
			for(int right = 1; right <= r; right++){
				cur = getSum(left,right,sr,er);
				ans = min(ans, abs(a-cur) + abs(b-cur));
				while(cur > b){
					left++;
					cur = getSum(left,right,sr,er);
					ans = min(ans, abs(a-cur) + abs(b-cur));
				}	
				cur = getSum(left,right,sr,er);
				ans = min(ans, abs(a-cur) + abs(b-cur));
			}		
		
		}
	cout<<ans<<"\n";

	return 0;
}
/*
[  ]Leu o problema certo???
[  ]Ver se precisa de long long
[  ]Viu o limite dos fors (é n? é m?)
[  ]Tamanho do vetor, será que é 2e5 em vez de 1e5??
[  ]Testar sample
[  ]Testar casos de  borda
[  ]1LL no 1LL << i
[  ]Testar mod (é 1e9+7, mesmo?, será que o mod não ficou negativo?)
*/

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 40 / 40