이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define pii pair<int, int>
#define pll pair<ll, ll>
#define F first
#define S second
using namespace std;
const ll mod = 1'000'000'007;
ll N, M, dp[500005][26], pre[500005][2], ans;
signed main()
{
ios::sync_with_stdio(0);
cin.tie(0), cout.tie(0);
cin >> N >> M;
vector<pii> v[2];
for(int i = 1; i <= M; i++)
{
int a, b;
cin >> a >> b;
if(a < b)
v[0].emplace_back(pii(a, b));
else
v[1].emplace_back(pii(b, a));
}
for(int t = 0; t <= 1; t++)
{
sort(v[t].begin(), v[t].end(), [](pii p1, pii p2){ return p1.S < p2.S; });
multiset<int, greater<int>> st;
st.insert(0);
for(int i = N; i >= 1; i--)
{
while(!v[t].empty() && v[t].back().S >= i)
{
st.insert(v[t].back().F);
v[t].pop_back();
}
pre[i][t] = *st.upper_bound(i);
}
}
for(int i = 0; i < 26; i++)
dp[1][i] = 1;
for(int i = 2; i <= N; i++)
for(int j = 0; j < 26; j++)
{
for(int k = 0; k < 26; k++)
{
int mx = max(pre[i][0], pre[i][1]);
if(pre[i][0] <= pre[i][1])
{
if(j > k)
dp[i][j] = (dp[i][j] + dp[i - 1][k] - dp[mx][k] + mod) % mod;
if(j < k)
dp[i][j] = (dp[i][j] + dp[i - 1][k] - dp[pre[i][0]][k] + mod) % mod;
}
else
{
if(j > k)
dp[i][j] = (dp[i][j] + dp[i - 1][k] - dp[pre[i][1]][k] + mod) % mod;
if(j < k)
dp[i][j] = (dp[i][j] + dp[i - 1][k] - dp[mx][k] + mod) % mod;
}
}
dp[i][j] = (dp[i][j] + dp[i - 1][j]) % mod;
}
for(int j = 0; j < 26; j++)
ans = (ans + dp[N][j]) % mod;
cout << ans << '\n';
}
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