Submission #631871

#TimeUsernameProblemLanguageResultExecution timeMemory
631871zaneyuGenetics (BOI18_genetics)C++14
100 / 100
491 ms97340 KiB
/*input 4 3 1 ACC CCA ACA AAA */ #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; //order_of_key #of elements less than x // find_by_order kth element typedef unsigned long long int ll; #define ld long double #define pii pair<int,int> typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> indexed_set; #define f first #define s second #define pb push_back #define REP(i,n) for(int i=0;i<n;i++) #define REP1(i,n) for(int i=1;i<=n;i++) #define FILL(n,x) memset(n,x,sizeof(n)) #define ALL(_a) _a.begin(),_a.end() #define sz(x) (int)x.size() const ll maxn=5e3+5; const ll maxlg=__lg(maxn)+2; const ll INF64=4e18; const int INF=0x3f3f3f3f; const ll MOD=998244353; const ld PI=acos(-1); const ld eps=1e-9; #define lowb(x) x&(-x) #define MNTO(x,y) x=min(x,(__typeof__(x))y) #define MXTO(x,y) x=max(x,(__typeof__(x))y) #define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end())))) #define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin()) template<typename T1,typename T2> ostream& operator<<(ostream& out,pair<T1,T2> P){ out<<P.f+1<<' '<<P.s+1; return out; } template<typename T> ostream& operator<<(ostream& out,vector<T> V){ REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?"\n":""); return out; } int mult(ll a,ll b){ if(a<0) a+=MOD; return (a*b)%MOD; } ll mypow(ll a,ll b){ if(b<=0) return 1; ll res=1LL; while(b){ if(b&1) res=mult(res,a); a=mult(a,a); b>>=1; } return res; } int arr[maxn][maxn]; bool vis[maxn]; int k; mt19937_64 rng(69); bool ok[maxn]; ll val[maxn]; ll tot[4][maxn]; int32_t main(){ ios::sync_with_stdio(false),cin.tie(0); int n,m; cin>>n>>m>>k; REP(i,n){ REP(j,m){ char c; cin>>c; int v=0; if(c=='C') v=1; if(c=='G') v=2; if(c=='T') v=3; arr[i][j]=v; } ok[i]=1; } int cnt=n; while(cnt>1){ REP(i,n) val[i]=rng(); REP(a,4) REP(i,m) tot[a][i]=0; ll ts=0; REP(i,n){ ts+=val[i]; REP(j,m){ tot[arr[i][j]][j]+=val[i]; } } REP(i,n){ if(!ok[i]) continue; ll tmp=ts*m; REP(j,m) tmp-=tot[arr[i][j]][j]; if((ts-val[i])*k!=tmp) ok[i]=0,--cnt; } } REP(i,n){ if(ok[i]){ cout<<i+1; return 0; } } }
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