#include <bits/stdc++.h>
using namespace std;
#define MOD 1000000007
#define ll long long int
#define vi vector<int>
#define vii vector< vector<int> >
#define PI 3.1415926535897932384626433832795
#define INF 9223372036854775807LL
bool solved[51][20001];
int dp[20001][51];
int minval[20002][52][52];
int prefsum[20002];
int conssolved[51][20001]; //[x][y]=z means, the xth solved y-z+1,y-z+2,...,y tasks but not the y-z th
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
int n,t,s;
cin >> n >> t >> s;
vi p(t+1);
for(int i = 1; i <= t; i++) {
cin >> p[i];
prefsum[i] = prefsum[i-1]+p[i];
}
vector<vector<int> > solves (t+1,vi(n));
for(int i = 1; i <= n; i++) {
int lastnotsolv = 0;
for(int j = 1; j <= t; j++) {
char ch;
cin >> ch;
solved[i][j] = (ch == '1');
if(!solved[i][j]) {
lastnotsolv = j;
}
conssolved[i][j] = j-lastnotsolv;
}
}
for(int i = 1; i <= t; i++) {
for(int st = 1; st <= n; st++) {
solves[i][st-1] = (conssolved[st][i]);
}
sort(solves[i].begin(),solves[i].end());
}
int sum = 0;
for(int j = 0; j <= s; j++) {
for(int i = 0; i <= t; i++) {
for(int per = 0; per <= n; per++) {
minval[i][j][per] = 2*MOD;
}
}
}
for(int i = 1; i <= t; i++) {
sum+= p[i];
int solv = 0;
for(int j = 1; j <= n; j++) {
if(conssolved[j][i] == i) {
solv++;
}
}
dp[i][1] = solv*sum;
for(int pers = 0; pers <= n; pers++) {
minval[i][2][pers] = min(minval[i-1][2][pers]+pers*p[i],dp[i][1]);
}
}
for(int j = 2; j <= s; j++) {
for(int i = 1; i <= t; i++) {
// for(int st = 1; st <= n; st++) {
// solves[st-1] = (conssolved[st][i]);
// }
// sort(solves.begin(),solves.end());
int ind = 0;
sum = prefsum[i]-prefsum[i-1];
dp[i][j] = minval[i-1][j][n-ind]+sum*(n-ind);
for(int currsiz : solves[i]) {
currsiz++;
if(currsiz > i-j+1) {
break;
}
while(ind < n && solves[i][ind] < currsiz) {
ind++;
}
sum = prefsum[i]-prefsum[i-currsiz];
if(dp[i][j] == dp[i][j-1]) {
break;
}
dp[i][j] = min(dp[i][j],minval[i-currsiz][j][n-ind]+sum*(n-ind));
}
for(int pers = 0; pers <= n; pers++) {
minval[i][j+1][pers] = min(minval[i-1][j+1][pers]+pers*p[i],dp[i][j]);
}
}
}
for(int i = 1; i <= s; i++) {
cout << dp[t][i] << "\n";
}
return 0;
}
