이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
int n,m,i,j,d[505][505];
char a[505][505];
bool in(int x, int y)
{
return (x>0&&y>0&&x<=n&&y<=m);
}
int cod(char c)
{
if(c=='N')return 0;
if(c=='E')return 1;
if(c=='S')return 2;
if(c=='W')return 3;
return 4;
}
int cost(char a, int b)
{
return (b-cod(a)+4)%4;
}
int dx[4]={-1,0,1,0},dy[4]={0,1,0,-1};
struct cmp{
bool operator()(pair<int,int> a, pair<int,int> b)
{
return (d[a.first][a.second]>d[b.first][b.second]);
}
};
priority_queue<pair<int,int>, vector<pair<int,int> >, cmp> pq;
bool vis[505][505];
void solve()
{
cin>>n>>m;
for(i=1;i<=n;i++)
{
cin>>(a[i]+1);
for(j=1;j<=m;j++)
d[i][j]=10000000;
}
if(a[1][1]=='X')
{
if(n==1&&m==1)
cout<<0<<'\n';
else cout<<-1<<'\n';
return;
}
d[1][1]=0;
pq.push(make_pair(1,1));
while(!pq.empty())
{
int x=pq.top().first;
int y=pq.top().second;
pq.pop();
if(a[x][y]=='X'||vis[x][y])
continue;
vis[x][y]=1;
for(int i=0;i<4;i++)
{
int nx=x+dx[i];
int ny=y+dy[i];
if(!in(nx,ny))continue;
int nc=d[x][y]+cost(a[x][y],i);
if(nc<d[nx][ny])
{
d[nx][ny]=nc;
if(a[nx][ny]!='X')
pq.push(make_pair(nx,ny));
}
}
}
cout<<(d[n][m]==10000000?-1:d[n][m])<<'\n';
}
signed main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
solve();
return 0;
}
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