제출 #628812

#제출 시각아이디문제언어결과실행 시간메모리
628812vovamrIzbori (COCI22_izbori)C++17
40 / 110
3037 ms18056 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #define fi first #define se second #define ll long long #define ld long double #define sz(x) ((int)(x).size()) #define all(x) (x).begin(), (x).end() #define pb push_back #define mpp make_pair #define ve vector using namespace std; using namespace __gnu_pbds; template<class T> using oset = tree<T,null_type,less_equal<T>,rb_tree_tag,tree_order_statistics_node_update>; const ll inf = 1e18; const int iinf = 1e9; typedef pair<ll, ll> pll; typedef pair<int, int> pii; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); template <typename T> inline bool chmin(T& a, T b) { return (a > b ? a = b, 1 : 0); } template <typename T> inline bool chmax(T& a, T b) { return (a < b ? a = b, 1 : 0); } const int N = 2e5 + 10; int a[N]; ll ans = 0; ve<int> occ[N]; inline static ll F(const int &l, const int &r) { return (l + r) * 1ll * (r - l + 1) / 2ll; } inline void cnt(const int &l1, const int &r1, const int &l2, const int &r2, const int &C) { int R = min(r2, r1 + C - 1); int L = max(l2, l1 + C); ans += max(0, R - l2 + 1) * 1ll * (r1 + 1); ans -= l1 * 1ll * max(0, min(R, l1 + C - 1) - l2 + 1); ans += max(0, R - L + 1) * 1ll * C; if (L <= R) ans -= F(L + 1, R + 1); } inline void solve() { int n; cin >> n; ve<int> al; for (int i = 0; i < n; ++i) cin >> a[i], al.pb(a[i]); sort(all(al)), al.erase(unique(all(al)), al.end()); for (int i = 0; i < n; ++i) a[i] = lower_bound(all(al), a[i]) - al.begin(); for (int i = 0; i < n; ++i) occ[a[i]].pb(i); const int b = 2000; ve<int> p(n); for (int el = 0; el < sz(al); ++el) { if (sz(occ[el]) > b) { oset<int> st; st.insert(0); for (int i = 0; i < n; ++i) { p[i] = (a[i] == el ? 1 : -1); if (i) p[i] += p[i - 1]; ans += st.order_of_key(p[i]); st.insert(p[i]); } } else { for (int l = 0; l < sz(occ[el]); ++l) { for (int r = l; r < sz(occ[el]); ++r) { int r1 = occ[el][l] - 1, l1 = (!l ? -1 : occ[el][l - 1]); int l2 = occ[el][r], r2 = (r + 1 == sz(occ[el]) ? n - 1 : occ[el][r + 1] - 1); cnt(l1, r1, l2, r2, 2 * (r - l + 1)); } } } } cout << ans; } signed main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); int q = 1; // cin >> q; while (q--) solve(); cerr << fixed << setprecision(3) << "Time execution: " << (double)clock() / CLOCKS_PER_SEC << endl; }
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