이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<iostream>
#include<cmath>
#include<algorithm>
#include<stack>
using namespace std;
#define MASK(i) (1LL << (i))
#define BIT(x, i) (((x) >> (i)) & 1)
#define fi first
#define se second
#define ll long long
#define mp make_pair
#define pb push_back
#define ii pair<int, int>
#define task "test"
const int inf = 1e9 + 7;
const ll infll = (ll)1e18 + 7;
const int MOD = 1e9 + 7;
const int N = 2e6 + 3;
template <typename T1, typename T2> bool minimize(T1 &a, T2 b){if (a > b) {a = b; return true;} return false;}
template <typename T1, typename T2> bool maximize(T1 &a, T2 b){if (a < b) {a = b; return true;} return false;}
int n;
ll a[N], dp[3005][3005];
/*void update(int x,int y,int val) {
while(x <= n) {
maximize(bit[x][y], val);
x += (x & -x);
}
}
ll get(int y,int l,int r) {
int ans = -inf;
while(l <= r) {
if(r - (r & -r) >= l) {
maximize(ans, bit[r][y]);
r -= (r & -r);
} else {
maximize(ans, dp1[r][y]);
r--;
}
}
return ans;
}
void sol1() {
for(int i=1;i<=n;i++) {
for(int j=1;j<=i;j++) {
if(j == 1) {
dp1[j][i] = 1;
update(j, i, dp1[j][i]);
continue;
}
ll sum = a[i] - a[j-1];
//for(int k=1;k<j;k++) {
//ll preSum = a[j-1] - a[k-1];
//if(preSum <= sum) maximize(dp[j][i], dp[k][j-1] + 1);
//}
int l = 1;
int r = j - 1;
int pos = -1;
while(l <= r) {
int mid = (l + r) / 2;
if(a[j-1] - a[mid - 1] <= sum) {
pos = mid;
r = mid - 1;
} else l = mid + 1;
}
cout<<j<<" "<<i<<" "<<pos<<'\n';
if(pos != -1) dp1[j][i] = get(j-1, pos, j-1) + 1;
maximize(dp1[j][i], 0);
if(dp1[j][i] == 0) dp1[j][i] = -inf;
update(j, i, dp1[j][i]);
}
}
ll ans = 0;
for(int i=1;i<=n;i++) ans += dp1[i][n];
cout<<ans;
}*/
int main()
{
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
cin>>n;
for(int i=1;i<=n;i++) {
cin>>a[i];
a[i] += a[i-1];
}
for(int i=1;i<=n;i++) {
for(int j=1;j<=i;j++) {
if(j == 1) {
dp[j][i] = 1;
continue;
}
ll sum = a[i] - a[j-1];
for(int k=j-1;k>0;k--) {
ll preSum = a[j-1] - a[k-1];
if(preSum <= sum) maximize(dp[j][i], dp[k][j-1] + 1); else break;
}
if(dp[j][i] == 0) dp[j][i] = -inf;
}
}
ll res = 0;
for(int i=1;i<=n;i++) maximize(res, dp[i][n]);
cout<<res;
return 0;
}
/* 10
4 1 2 4 2 3 5 6 8 10 */
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