oj.uz

답안 #627290

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
627290 2022-08-12T11:54:24 Z AA_Surely Sumtree (INOI20_sumtree) C++14
10 / 100
 3000 ms 93800 KB 
#include <bits/stdc++.h>

#define FOR(i, x, n) for(int i = x; i < n; i++)
#define F0R(i, n) FOR(i, 0, n)
#define ROF(i, x, n) for(int i = n - 1; i >= x; i--)
#define R0F(i, n) ROF(i, 0, n)

#define WTF cout << "WTF" << endl

#define IOS ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define F first
#define S second
#define PB push_back

#define ALL(x) x.begin(), x.end()
#define RALL(x) x.rbegin(), x.rend()

using namespace std;

typedef long long LL;

typedef pair<int, int> PII;
typedef pair<LL, LL> PLL;

typedef vector<int> VI;
typedef vector<LL> VLL;
typedef vector<PII> VPII;
typedef vector<PLL> VPLL;

const int N = 5e5 + 7;
const int LOG = 22;
const int INF = 1e9 + 7;
const int MOD = 1e9 + 7;

#define lc now << 1
#define rc now << 1 | 1
#define endl '\n'

LL chs[N], vir[N], fact[N], ifact[N];
LL ans;
VI adj[N], order;
LL n, q, bad, cnt;
LL head[N], par[N], s[N], height[N];
LL t[N][2];

struct SumTree {
    LL tree[N << 2];

    void add(int lq, int rq, LL val, int now = 1, int ls = 0, int rs = n - 1) {
        if (rq < lq || rq < ls || rs < lq) return;
        if (lq <= ls && rs <= rq) {
            tree[now] += val;
            return;
        }

        int mid = (ls + rs) >> 1;
        add(lq, rq, val, lc, ls, mid);
        add(lq, rq, val, rc, mid + 1, rs);

        return;
    }

    LL get(int id, int now = 1, int ls = 0, int rs = n - 1) {
        if (ls == rs) return tree[now];
        int mid = (ls + rs) >> 1;
        if (id <= mid) return get(id, lc, ls, mid) + tree[now];
        return get(id, rc, mid + 1, rs) + tree[now];
    }
} val, sz;

struct DescendTree {
    bool tree[N << 2];
    bool arr[N];

    void ch(int id, bool val, int now = 1, int ls = 0, int rs = n - 1) {
        if (ls == rs) {
            tree[now] = val;
            return;
        }

        int mid = (ls + rs) >> 1;
        if (ls <= mid) ch(id, val, lc, ls, mid);
        else ch(id, val, rc, mid + 1, rs);

        tree[now] = tree[lc] | tree[rc];
        return;
    }

    void change(int id, int val) {
        ch(id, val);
        arr[id] = val;
    }

    int g(int x) {
        return arr[x];
    }

    int rightest(int q, int now = 1, int ls = 0, int rs = n - 1) {
        if (ls > q || !tree[now]) return n;
        if (ls == rs) return ls;
        int mid = (ls + rs) >> 1;
        int case1 = rightest(q, rc, mid + 1, rs);
        return (case1 == n ? rightest(q, lc, ls, mid) : case1);
    }
} active;

inline int pw(LL a, int b) {
    LL ret = 1;
    for(; b; b >>= 1, a = a * a % MOD)
        if (b & 1) ret = ret * a % MOD;
    return ret;
}

inline int nCr(int nn, int rr) {
    if (nn < rr || rr < 0) return 0;
    return (fact[nn] * ifact[rr] % MOD) * ifact[nn - rr] % MOD;
}

void init() {
    LL v0;
    cin >> n >> v0;
    val.add(0, 0, v0);

    F0R(i, n - 1) {
        int u, v;
        cin >> u >> v;
        adj[--u].PB(--v);
        adj[v].PB(u);
    }

    cin >> q;

    ans = 1;
    return;
}

void preD(int now, int p, int h = 0) {
    par[now] = p;
    s[now] = 1;
    height[now] = h;
    for(int on : adj[now]) if (on != p) {
        preD(on, now, h + 1);
        s[now] += s[on];
    }
    return;
}

void precalc() {
    fact[0] = 1;
    FOR(i, 1, N) fact[i] = fact[i - 1] * i % MOD;
    ifact[N - 1] = pw(fact[N - 1], MOD - 2);
    R0F(i, N - 1) ifact[i] = ifact[i + 1] * (i + 1) % MOD;
    iota(head, head + n, 0);

    F0R(i, n) {
        sort(ALL(adj[i]), [](const int &a, const int &b) {return s[a] < s[b];});
        if (i) adj[i].pop_back();
        reverse(ALL(adj[i]));
    }

    return;
}

void dfs(int now) {
    order.PB(now);
    t[now][0] = cnt++;
    //if (!adj[now].empty()) head[ adj[now][0] ] = head[now];

    for(int on : adj[now]) dfs(on);

    t[now][1] = cnt;
    return;
}

void updChoose(int now) {
    if (!chs[now]) bad--;
    else ans = (ans * pw(chs[now], MOD - 2)) % MOD;
    
    LL val_now = val.get(t[now][0]);
    LL sz_now = sz.get(t[now][0]);
    chs[now] = nCr(val_now + sz_now - 1, sz_now - 1);

    if (!chs[now]) bad++;
    else ans = (ans * chs[now]) % MOD;

    return;
}

void remChoose(int now) {
    if (!chs[now]) bad--;
    else ans = (ans * pw(chs[now], MOD - 2)) % MOD;

    chs[now] = 1;

    return;
}

int getUpperActive(int v) {
    while(!active.g(v)) {
        int pl = order[ active.rightest(t[v][0]) ];
        if (t[pl] >= t[ head[v] ]) v = pl;
        else v = par[ head[v] ];
    }

    return v;
}

void addUpTo(int v, int z, int x1, LL x2) {
    while(height[v] >= height[z]) {
        int w = (height[ head[v] ] >= height[z] ? head[v] : z);
        sz.add(t[w][0], t[v][0], x1);
        val.add(t[w][0], t[v][0], x2);

        v = par[w];
    }

    return;
}

void addTag() {
    int v, x;
    cin >> v >> x;
    v--;
    
    val.add(t[v][0], t[v][0], x);
    LL sz_v = sz.get(t[v][0]);
    LL val_v = val.get(t[v][0]);

    int up = getUpperActive(v);
    addUpTo(par[v], up, -sz_v, -val_v);
    
    vir[v] = x;

    updChoose(up);
    updChoose(v);

    active.change(t[v][0], 1);
    return;
}

void remTag() {
    int v;
    cin >> v; 
    v--;

    LL sz_v = sz.get(t[v][0]);
    LL val_v = val.get(t[v][0]);

    int up = getUpperActive(par[v]);
    addUpTo(par[v], up, sz_v, val_v);

    val.add(t[v][0], t[v][0], -vir[v]);

    updChoose(up);
    remChoose(v);

    active.change(t[v][0], 0);
    return;
}

int main() {
    IOS;

    init();

    height[n] = -1;
    par[0] = n;

    preD(0, n);
    precalc();
    dfs(0);

    F0R(i, n) sz.add(t[i][0], t[i][0], s[i]);

    active.change(0, 1);
    fill(chs, chs + n, 1);
    updChoose(0);

    cout << ans << endl;

    while(q--) {
        int tp; cin >> tp;
        if (tp == 1) addTag();
        else remTag();

        cout << (bad ? 0 : ans) << endl;
    }
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 215 ms 49084 KB Output is correct
2 Correct 169 ms 48960 KB Output is correct
3 Correct 188 ms 49092 KB Output is correct
4 Correct 193 ms 49008 KB Output is correct
5 Correct 150 ms 45056 KB Output is correct
6 Correct 17 ms 20520 KB Output is correct
7 Correct 17 ms 20308 KB Output is correct
8 Correct 19 ms 20348 KB Output is correct
9 Correct 239 ms 41396 KB Output is correct
10 Correct 183 ms 41292 KB Output is correct
11 Correct 184 ms 41412 KB Output is correct
12 Correct 182 ms 40420 KB Output is correct
13 Correct 157 ms 47204 KB Output is correct

Subtask #2
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 16 ms 19924 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 667 ms 53272 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3037 ms 93800 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #5
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 215 ms 49084 KB Output is correct
2 Correct 169 ms 48960 KB Output is correct
3 Correct 188 ms 49092 KB Output is correct
4 Correct 193 ms 49008 KB Output is correct
5 Correct 150 ms 45056 KB Output is correct
6 Correct 17 ms 20520 KB Output is correct
7 Correct 17 ms 20308 KB Output is correct
8 Correct 19 ms 20348 KB Output is correct
9 Correct 239 ms 41396 KB Output is correct
10 Correct 183 ms 41292 KB Output is correct
11 Correct 184 ms 41412 KB Output is correct
12 Correct 182 ms 40420 KB Output is correct
13 Correct 157 ms 47204 KB Output is correct
14 Incorrect 16 ms 19924 KB Output isn't correct
15 Halted 0 ms 0 KB -