This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// correct/solution-prabowo-inverse.cpp
// O(N + M log MOD + Q log M)
#include "circuit.h"
#include <functional>
#include <utility>
#include <vector>
const int kMod = 1000002022;
const int kPhiMod = kMod / 2 / 223 * 222 / 2242157 * 2242156;
int power(int x, int y) {
int result = 1;
for (; y > 0; y >>= 1) {
if (y & 1) {
result = static_cast<long long>(result) * x % kMod;
}
x = static_cast<long long>(x) * x % kMod;
}
return result;
}
struct Z {
int c, e2, e223;
Z(int val=1) {
e2 = 0, e223 = 0, c = val;
while (c % 2 == 0) {
++e2;
c /= 2;
}
while (c % 223 == 0) {
++e223;
c /= 223;
}
}
Z& operator *= (const Z &rhs) {
c = static_cast<long long>(c) * rhs.c % kMod;
e2 += rhs.e2;
e223 += rhs.e223;
return *this;
}
friend Z operator / (Z lhs, Z rhs) {
lhs.c = static_cast<long long>(lhs.c) * power(rhs.c, kPhiMod - 1) % kMod;
lhs.e2 -= rhs.e2;
lhs.e223 -= rhs.e223;
return lhs;
}
int value() {
return static_cast<long long>(c) *
power(2, e2) % kMod * power(223, e223) % kMod;
}
};
int N;
struct SegTree {
private:
int n;
struct Node {
int val[2];
bool lazy;
Node(int v0=0, int v1=0) {
val[0] = v0;
val[1] = v1;
lazy = false;
}
Node operator + (const Node &other) {
return Node((val[0] + other.val[0]) % kMod,
(val[1] + other.val[1]) % kMod);
}
};
std::vector<Node> nodes;
inline void toggle(int idx) {
std::swap(nodes[idx].val[0], nodes[idx].val[1]);
nodes[idx].lazy = !nodes[idx].lazy;
}
inline void pull(int idx, int l, int r) {
int mid = (l + r) >> 1;
nodes[idx] = nodes[idx + 1] + nodes[idx + (mid - l) * 2];
}
inline void push(int idx, int l, int r) {
if (!nodes[idx].lazy) return;
int mid = (l + r) >> 1;
toggle(idx + 1);
toggle(idx + (mid - l) * 2);
nodes[idx].lazy = false;
}
void build(int idx, int l, int r, const std::vector<std::pair<int, int>> &v) {
if (l + 1 == r) {
nodes[idx] = Node(v[l].first, v[l].second);
return;
}
int mid = (l + r) >> 1;
build(idx + 1, l, mid, v);
build(idx + (mid - l) * 2, mid, r, v);
pull(idx, l, r);
}
void update(int idx, int l, int r, int ll, int rr) {
if (l >= rr || r <= ll) {
return;
}
if (l >= ll && r <= rr) {
return toggle(idx);
}
push(idx, l, r);
int mid = (l + r) >> 1;
update(idx + 1, l, mid, ll, rr);
update(idx + (mid - l) * 2, mid, r, ll, rr);
pull(idx, l, r);
}
public:
void init(const std::vector<std::pair<int, int>> &v) {
n = static_cast<int>(v.size());
nodes.resize(2 * n - 1);
build(0, 0, n, v);
}
void update(int l, int r) {
update(0, 0, n, l, r);
}
int query() {
return nodes[0].val[1];
}
} segtree;
void init(int _N, int M, std::vector<int> P, std::vector<int> A) {
N = _N;
std::vector<std::vector<int>> adj(N + M);
for (int i = 1; i < N + M; ++i) {
adj[P[i]].push_back(i);
}
Z product;
for (int i = 0; i < N; ++i) {
product *= Z(static_cast<int>(adj[i].size()));
}
std::vector<int> contribution(M);
std::function<void(int, Z)> dfs = [&](int u, Z path) {
if (u >= N) {
contribution[u - N] = (product / path).value();
return;
}
path *= Z(static_cast<int>(adj[u].size()));
for (int v : adj[u]) {
dfs(v, path);
}
};
dfs(0, Z());
std::vector<std::pair<int, int>> v(M);
for (int i = 0; i < M; ++i) {
if (A[i]) {
v[i].second = contribution[i];
} else {
v[i].first = contribution[i];
}
}
segtree.init(v);
}
int count_ways(int L, int R) {
segtree.update(L - N, R - N + 1);
return segtree.query();
}
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