제출 #625300

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
625300		Trunkty	슈퍼트리 잇기 (IOI20_supertrees)	C++14	19 / 100	230 ms	24084 KiB

supertrees

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
typedef long long ll;
//#define int ll

#include "supertrees.h"

int root[1005];
vector<int> ans[1005];

int findroot(int x){
    if(root[x]!=x){
        root[x] = findroot(root[x]);
    }
    return root[x];
}

void domerge(int a, int b){
    a = findroot(a);
    b = findroot(b);
    root[a] = b;
}

int construct(vector<vector<int>> p) {
	int n = p.size();
	vector<vector<int>> ret;
	for (int i = 0; i < n; i++) {
		vector<int> row;
		row.resize(n);
		ret.push_back(row);
	}
    for(int i=0;i<n;i++){
        root[i] = i;
    }
	for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            if(p[i][j]){
                domerge(i,j);
            }
        }
    }
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            if(p[i][j]==0 and findroot(i)==findroot(j)){
                return 0;
            }
        }
    }
    for(int i=0;i<n;i++){
        ans[findroot(i)].push_back(i);
    }
    for(int i=0;i<n;i++){
        for(int j=1;j<ans[i].size();j++){
            ret[ans[i][j-1]][ans[i][j]] = 1;
            ret[ans[i][j]][ans[i][j-1]] = 1;
        }
        if(ans[i].size()<=1){
            continue;
        }
        else if(ans[i].size()==2){
            return 0;
        }
        else{
            ret[ans[i][0]][ans[i].back()] = 1;
            ret[ans[i].back()][ans[i][0]] = 1;
        }
    }
    build(ret);
	return 1;
}

컴파일 시 표준 에러 (stderr) 메시지

supertrees.cpp: In function 'int construct(std::vector<std::vector<int> >)':
supertrees.cpp:55:22: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   55 |         for(int j=1;j<ans[i].size();j++){
      |                     ~^~~~~~~~~~~~~~

• Subtask 1: 0 / 11
• Subtask 2: 0 / 10
• Subtask 3: 19 / 19
• Subtask 4: 0 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4