제출 #624354

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
624354		yuto1115	휴가 (IOI14_holiday)	C++17	0 / 100	366 ms	65536 KiB

holiday

#include"holiday.h"
#include <bits/stdc++.h>
#define rep(i, n) for(ll i = 0; i < ll(n); ++i)
#define rep2(i, s, n) for(ll i = ll(s); i < ll(n); ++i)
#define rrep(i, n) for(ll i = ll(n) - 1; i >= 0; --i)
#define rrep2(i, n, t) for(ll i = ll(n) - 1; i >= ll(t); --i)
#define pb push_back
#define eb emplace_back
#define SZ(a) int(a.size())
#define all(a) a.begin(), a.end()
using namespace std;
using ll = long long;
using P = pair<int, int>;
using vi = vector<int>;
using vvi = vector<vi>;
using vl = vector<ll>;
using vvl = vector<vl>;
using vp = vector<P>;
using vvp = vector<vp>;
using vb = vector<bool>;
using vvb = vector<vb>;
using vs = vector<string>;
const int inf = 1001001001;
const ll linf = 1001001001001001001;

template<class T>
bool chmin(T &a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

template<class T>
bool chmax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

vl get_max(const vi &v, int d, int s) {
    int n = SZ(v);
    vl res(d + 1);
    if (!n) return res;
    vvi ls(n, vi(n + 1));
    multiset<int> st;
    rep(i, n) {
        st.insert(v[i]);
        auto it = st.end();
        rep(j, i + 1) {
            --it;
            ls[i][j + 1] = ls[i][j] + *it;
        }
    }
    auto f = [&](int i, int num) -> ll {
        assert(0 <= i and i < n);
        assert(0 <= num);
        return ls[i][min(num, i + 1)];
    };
//    int now = 0;
    rep2(i, s, d + 1) {
        rep(j, n) {
            if (s * (j + 1) > i) break;
            chmax(res[i], f(j, i - s * (j + 1)));
        }
//        res[i] = f(now, i - s * (now + 1));
//        while (now + 1 < n and s * (now + 2) <= i) {
//            ll l = f(now + 1, i - s * (now + 2));
//            if (chmax(res[i], l)) ++now;
//            else break;
//        }
    }
    return res;
}

ll findMaxAttraction(int n, int start, int d, int attraction[]) {
    vi l, r;
    rrep(i, start) l.pb(attraction[i]);
    rep2(i, start + 1, n) r.pb(attraction[i]);
    ll ans = 0;
    rep(_, 2) {
        vl x = get_max(l, d, 1);
        vl y = get_max(r, d, 2);
        rep(i, d + 1) chmax(ans, x[i] + y[d - i]);
        rep(i, d) chmax(ans, x[i] + y[d - 1 - i] + attraction[start]);
        swap(l, r);
    }
    return ans;
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 23
• Subtask 3: 0 / 17
• Subtask 4: 0 / 53