Submission #624092

#TimeUsernameProblemLanguageResultExecution timeMemory
624092jophyyjhPacking Biscuits (IOI20_biscuits)C++14
21 / 100
1093 ms45624 KiB
/** * Binary. Hmm, interesting. I started with [S2], which I solved with recursion in * O(kq). The basic idea is to treat two 2^i biscuits in the bag as one 2^(i+1). * * A few greedy observations: * (1) Given x, can we determine if it's possible? Well, we can simply iterate i * from large to small. If the additional tastiness x we still need for a * certain bag satisfies x >= 2^i, put a biscuit 2^i in the bag if there's one. * (2) Biscuits of the same type can be distributed as evenly as possible, i.e. * there is an optimal partition s.t. for every i * |#2^i_biscuits_in_bag_1 - #2^i_biscuits_in_big_2| <= 1. * (3) Unlike (1), (2), we consider from small to large. If x is odd, each bag needs * at least 1 2^0 biscuit. After that, every 2 2^O biscuits can be grouped to * form 1 2^1 biscuit, so we can add this num to the original num of 2^1 * biscuits. Well, let's write this recursively: * def find(): * total = 0 * if #2^0 >= x: * add floor((#2^0 - x) / 2) to #2^1 and recurse downdwards * add floor(#2^0 / 2) to 2^1 and recurse downwards * ... * * Can we AC this problem with (3)? I guess that the num of configurations given to * find() isn't too many, so we can optimize it with memoization. Indeed, we can * prove that in each level of find(), the num. of unique calls the next level of * find() is bounded by x. This is because x >= x/2 + x/4 + x/8 + x/16 + .... [S1-3] * are solved. * * In impl1, the function search(p, first) doesn't decrease as first increases. * Furthermore, if search(p, w) and search(p, z) are both called, |w-z| <= x. * * Time Complexity: O(xqk * log(xk)) (partial solution) * Implementation 1 (Only solves [S1-3], may solve [S4]) */ #include <bits/stdc++.h> #include "biscuits.h" typedef long long ll; ll x; std::vector<ll> a; struct pair_t { int p; ll first; }; inline bool operator<(const pair_t& p1, const pair_t& p2) { return p1.p < p2.p || (p1.p == p2.p && p1.first < p2.first); } std::map<pair_t, ll> cache; inline ll search(int p, ll first) { if (cache.find(pair_t{p, first}) == cache.end()) { int k = a.size(); if (p == k - 1) return first / x + 1; ll total = search(p + 1, a[p + 1] + first / 2); if (first >= x) total += search(p + 1, a[p + 1] + (first - x) / 2); cache[pair_t{p, first}] = total; } return cache[pair_t{p, first}]; } ll count_tastiness(ll _x, std::vector<ll> _a) { cache.clear(); x = _x, a = _a; return search(0, a[0]); }
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