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답안 #624074

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
624074 2022-08-07T08:03:44 Z jiahng Uplifting Excursion (BOI22_vault) C++14
0 / 100
 1 ms 340 KB 
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
#define int ll
typedef pair<int,int> pi;
typedef vector <int> vi;
typedef vector <pi> vpi;
typedef pair<pi, ll> pii;
typedef set <ll> si;
typedef long double ld;
#define f first
#define s second
#define mp make_pair
#define FOR(i,s,e) for(int i=s;i<=int(e);++i)
#define DEC(i,s,e) for(int i=s;i>=int(e);--i)
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define lbd(x, y) lower_bound(all(x), y)
#define ubd(x, y) upper_bound(all(x), y)
#define aFOR(i,x) for (auto i: x)
#define mem(x,i) memset(x,i,sizeof x)
#define fast ios_base::sync_with_stdio(false),cin.tie(0),cout.tie(0)
#define maxn 311
#define INF (ll)(1e18+10)
#define MOD 998244353
typedef pair <vi, int> pvi;
typedef pair <int,pi> ipi;
typedef vector <pii> vpii;
typedef pair <pi,pi> pipi;

int dp[2][maxn*maxn*4];
int A[maxn*2];
int M,L;
int32_t main(){
    fast;
    cin >> M >> L;
    FOR(i,0,2*M) cin >> A[i];
    vector <pii> v;
    int ans = 0,sm=0;
    FOR(i,M,2*M) if (sm <= L){
        int x = INF;
        if (i != M){
            x = (L - sm) / (i - M);
        }
        x = min(x, A[i]);
        sm += x * (i-M); 
        A[i] -= x;
        v.pb(pii(pi(-(i-M), x), -1));
        ans += x;
        assert(sm <= L+M);
        if (A[i] > 0 && sm < L){
            sm += i - M; A[i]--; ans++;
            v.pb(pii(pi(-(i-M),1),-1));
            assert(sm <= L + M && sm >= L);
            break;
        }
    }
    //cout << sm << ' ' << ans << '\n';
    if (sm < L){
        cout << "impossible"; return 0;
    }

    FOR(i,0,2*M) v.pb(pii(pi(i-M, A[i]), 1));
    
    vpi v2;
    aFOR(i,v){
        int x = min(2 * M, i.f.s);
        for (int k = 0; (1 << k) <= x; k++){
            v2.pb(pi((1<<k) * i.f.f, (1<<k)*i.s));
            x -= (1 << k);
        }
        if (x > 0) v2.pb(pi(x * i.f.f, x*i.s));
    }

    FOR(i,0,4*M*M) dp[0][i] = -INF;
    dp[0][M] = 0;
    
    aFOR(i,v2){
        FOR(j,0,4*M*M) if (j - i.f >= 0 && j - i.f <= 4*M*M) dp[1][j] = max(dp[0][j], dp[0][j-i.f] + i.s);
        FOR(j,0,4*M*M) dp[0][j] = dp[1][j];
    }
    
    ans += dp[0][L-sm+M];

    if (ans < 0) cout << "impossible";
    else cout << ans;

}

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3-1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Incorrect 1 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #3-2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Incorrect 1 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #4-1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Incorrect 1 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #4-2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5-1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Incorrect 1 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #5-2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #6-1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Incorrect 1 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #6-2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -