이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC target("sse,sse2,avx2")
#pragma GCC optimize("unroll-loops,O2")
#define rep(i,l,r) for (int i = l; i < r; i++)
#define repr(i,r,l) for (int i = r; i >= l; i--)
#define X first
#define Y second
#define all(x) (x).begin() , (x).end()
#define pb push_back
#define endl '\n'
#define debug(x) cerr << #x << " : " << x << endl;
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pll;
constexpr int N = 1e5+10,mod = 998244353,inf = 1e9+10,sq = 700;
inline int mkay(int a,int b){
if (a+b >= mod) return a+b-mod;
if (a+b < 0) return a+b+mod;
return a+b;
}
inline int poww(int a,int k){
if (k < 0) return 0;
int z = 1;
while (k){
if (k&1) z = 1ll*z*a%mod;
a = 1ll*a*a%mod;
k /= 2;
}
return z;
}
int a[N],b[N],ans[N],ind[N],c[N];
ordered_set seg[N*4];
pair<pll,pll> Q[N];
vector<int> vec,vea;
bool cmpc(int i,int j){
return (c[i] > c[j]);
}
bool cmpa(int i,int j){
return (a[i] < a[j]);
}
void upd(int l,int r,int p,int v = 1){
seg[v].insert(b[vea[p]]);
if (r-l == 1) return;
int m = (l+r) >> 1,u = (v << 1);
if (p < m) upd(l,m,p,u);
else upd(m,r,p,u|1);
}
int que(int l,int r,int s,int e,int B,int v = 1){
if (seg[v].empty() || l >= e || s >= r) return 0;
if (s <= l && r <= e){
return seg[v].size()-seg[v].order_of_key(B);
}
int m = (l+r) >> 1,u = (v << 1);
return que(l,m,s,e,B,u)+que(m,r,s,e,B,u|1);
}
int main(){
ios :: sync_with_stdio(0); cin.tie(0);
int n,q;
cin >> n >> q;
vector<pll> ub;
rep(i,0,n){
cin >> a[i] >> b[i];
c[i] = a[i]+b[i];
vec.pb(i);
vea.pb(i);
ub.pb({b[i],i});
}
sort(all(vec),cmpc);
sort(all(vea),cmpa);
rep(i,0,n) ind[vea[i]] = i;
rep(i,0,q){
cin >> Q[i].Y.X >> Q[i].Y.Y >> Q[i].X.X;
Q[i].X.Y = i;
ub.pb({Q[i].Y.Y,-n-i});
}
sort(all(ub));
rep(i,0,n+q){
if(ub[i].Y >= 0){
b[ub[i].Y] = i;
}
else{
Q[-ub[i].Y-n].Y.Y = i;
}
}
sort(Q,Q+q);
reverse(Q,Q+q);
int po = 0;
rep(i,0,q){
int C = Q[i].X.X,A = Q[i].Y.X,B = Q[i].Y.Y;
while (po < n && c[vec[po]] >= C){
upd(0,n,ind[vec[po]],1);
po++;
}
int l = -1,r = n,m;
while (r-l > 1){
m = (l+r) >> 1;
if (A <= a[vea[m]]) r = m;
else l = m;
}
ans[Q[i].X.Y] = que(0,n,r,n,B);
}
rep(i,0,q) cout << ans[i] << endl;
}
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