Submission #623805

#	Time	Username	Problem	Language	Result	Execution time	Memory
623805		Vladth11	Roads (CEOI20_roads)	C++14	0 / 100	1 ms	340 KiB

roads

#include <bits/stdc++.h>
#define C 1
#define P 0
#define debug(x) cerr << #x << " " << x << "\n"
#define debugs(x) cerr << #x << " " << x << " "
 
using namespace std;
typedef long long ll;
typedef pair <long double, long double> pii;
 
const ll NMAX = 100001;
const ll VMAX = 101;
const ll INF = (1LL << 60);
const ll MOD = 1000000007;
const ll BLOCK = 447;
const ll base = 117;
const ll nr_of_bits = 18;
const ll inv2 = 500000004;
 
map <pii, pii> mp;
pii v[NMAX * 2];
 
struct ura{
    pii a, b;
};
 
const long double pi = 3.14159265358979323846;
 
vector <ura> sol;
map <pii, bool> scutit;
long double slope = 1;
 
bool mic(pii a, pii b){
    return a < b;
}
 
bool cmp(pii a, pii b){
    return (mic(a, b));
}
 
long double dd(pii a, pii b){
    return sqrt((a.first - b.first) * (a.first - b.first) + (a.second - b.second) * (a.second - b.second));
}
 
map <pii, pair <int, int> > cine;
 
long double tg(long double x){
  return sin(x) / cos(x);
}
 
int main() {
    //ifstream cin(".in");
    //ofstream cout(".out");
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int n, i;
    cin >> n;
    for(i = 1; i <= n; i++){
        pii a, b;
        cin >> a.first >> a.second >> b.first >> b.second;
        if(mic(a, b))
            swap(a, b);
        if(b.second != a.second){
            slope = (a.first - b.first) /  (a.second - b.second);
        }
        pii d;
        d.first = a.first * tg(slope);
        d.second = a.second * tg(slope);
        cine[d] = a;
        a = d;
        v[i] = a;
        pii c = {a.first, 0};
        c.second = a.second +dd(a, b);
        cine[c] = b;
        b = c;
        mp[a] = b;
        mp[b] = a;
    }
    sort(v + 1, v + n + 1, cmp);
    for(i = 1; i < n; i++){
        sol.push_back({v[i], mp[v[i + 1]]});
    }
    for(auto x : sol){
        cout << cine[x.a].first << " " << cine[x.a].second << " " << cine[x.b].first << " " << cine[x.b].second << "\n";
    }
    return 0;
}

• Subtask 1: 0 / 0
• Subtask 2: 0 / 15
• Subtask 3: 0 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 15
• Subtask 6: 0 / 40