제출 #62246

#제출 시각아이디문제언어결과실행 시간메모리
62246BenqXOR Sum (info1cup17_xorsum)C++11
100 / 100
1138 ms54276 KiB

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 1000001;

int N, x;
array<int,MX> A, A2;

int get(int ind) {
    int cur = 0;
    if (ind < 0) cur -= 2*x, ind += N;
    if (ind >= N) cur += 2*x, ind -= N;
    return (A[ind]&(2*x-1))+cur;
}

void sor() {
    int co = 0;
    F0R(i,N) if (!(A[i]&x)) co ++;
    int co0 = 0;
    F0R(i,N) {
        if (!(A[i]&x)) A2[co0++] = A[i];
        else A2[co++] = A[i];
    }
    swap(A,A2);
}

ll tri() {
    sor();
    ll tot = 0;
    F0R(i,N) if ((2*A[i])&x) tot ++;
    int i1 = -N, i2 = -N; // first one >= x-i, first one >= 2*x-i
    F0Rd(i,N) {
        int v = A[i]&(2*x-1);
        while (get(i1) < x-v) i1 ++;
        while (get(i2) < 2*x-v) i2 ++;
        tot += i2-i1;
    }
    return tot/2;
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N; 
    F0R(i,N) {
        // A[i] = rand() % (1<<29);
        cin >> A[i];
    }
    int ans = 0;
    F0R(i,30) {
        x = 1<<i;
        if (tri()&1) ans ^= x;
    }
    cout << ans;
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
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