Submission #618905

#	Time	Username	Problem	Language	Result	Execution time	Memory
618905		CSQ31	Team Contest (JOI22_team)	C++17	37 / 100	2062 ms	24508 KiB

team

#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define fi first
#define se second
#define sz(a) (int)(a.size())
#define all(a) a.begin(),a.end()
#define owo ios_base::sync_with_stdio(0);cin.tie(0);
typedef pair<int,int> pii;
typedef long long int ll;
const int MAXN = 5e5;
array<ll,3>pts1[MAXN],pts2[MAXN];
vector<array<ll,3>>a;
vector<int>crd[3];
//i have rectangle queries but i cant do it offline?
//i can but its double log on 2s
//ok try n^2 first
int sz0,sz1,sz2;
struct seg{
	vector<int>t;
	int n;
	seg(){}
	seg(int _n){
		n = _n;
		t.assign(4*n+1,-2e9);
	}
	void upd(int v,int pos,int l,int r,int val){
		if(l==r){
			t[v] = max(t[v],val);
			return;
		}
		int tm = (l+r)/2;
		if(pos<=tm)upd(2*v,pos,l,tm,val);
		else upd(2*v+1,pos,tm+1,r,val);
		t[v] = max(t[2*v],t[2*v+1]);
	}
	void upd2(int v,int pos,int l,int r,int val){
		if(l==r){
			t[v] = val;
			return;
		}
		int tm = (l+r)/2;
		if(pos<=tm)upd(2*v,pos,l,tm,val);
		else upd(2*v+1,pos,tm+1,r,val);
		t[v] = max(t[2*v],t[2*v+1]);
	}
	int query(int v,int l,int r,int tl,int tr){
		if(l>r)return -2e9;
		if(l==tl && r==tr)return t[v];
		int tm = (tl+tr)/2;
		if(r<=tm)return query(2*v,l,r,tl,tm);
		else if(l>tm)return query(2*v+1,l,r,tm+1,tr);
		else return max(query(2*v,l,tm,tl,tm),query(2*v+1,tm+1,r,tm+1,tr));
	}
}amx;
ll ans = -1;
vector<int>pts[MAXN];

void solve(int l,int r){
	if(l==r){
		return;
	}
	//all same a
	int mid = (l+r)/2;
	solve(l,mid);
	solve(mid+1,r);
	vector<pii>add,que;
	for(int i=l;i<=mid;i++){
		for(int x:pts[i])add.push_back({a[x][1],x});
	}
	for(int i=mid+1;i<=r;i++){
		for(int x:pts[i])que.push_back({a[x][1],x});
	}
	//b and c values in add must be bigger than queries b and c
	sort(all(add),greater<pii>());
	sort(all(que),greater<pii>());
	/*
	cout<<l<<" "<<r<<'\n';
	cout<<"in add"<<'\n';
	for(pii x:add)cout<<x.se<<" ";
	cout<<'\n';
	cout<<"in que"<<'\n';
	for(pii x:que)cout<<x.se<<" ";
	cout<<'\n';
	* */
	int ptr = -1;
	for(pii qq : que){
		while(ptr+1 < sz(add) && add[ptr+1].fi > qq.fi){ //add still has bigger b
			ptr++;
			int id = add[ptr].se;
			//cout<<"update:"<<'\n';
			//cout<<a[id][2]<<" "<<pts1[id][0]<<" "<<pts2[id][0]<<'\n';
			if(pts1[id][0]!=-2e9)amx.upd(1,pts1[id][2],0,sz2-1,pts1[id][0]);
			if(pts2[id][0]!=-2e9)amx.upd(1,pts2[id][2],0,sz2-1,pts2[id][0]);
		} 
		int id = qq.se;
		ll res = amx.query(1,a[id][2]+1,sz2-1,0,sz2-1); //we need a bigger ccout<<"query"<<'\n';
		if(a[id][2]+1 < sz2)ans = max(ans , crd[0][a[id][0]] + res);
	}
	for(pii x:add){
		int id = x.se;
		amx.upd2(1,a[id][2],0,sz2-1,-2e9);
	}
}
int main()
{
	owo
	int n;
	cin>>n;
	a.resize(n);
	for(int i=0;i<n;i++){
		for(int j=0;j<3;j++){
			cin>>a[i][j];
			crd[j].pb(a[i][j]);
		}
	}
	sort(all(a),[&](array<ll,3>i,array<ll,3>j){return j[0] > i[0];});
	for(int j=0;j<3;j++){
		sort(all(crd[j]));
		crd[j].resize(unique(all(crd[j])) - crd[j].begin());
	}
	//cout<<"sorted"<<'\n';
	//for(int i=0;i<n;i++)cout<<a[i][0]<<" "<<a[i][1]<<" "<<a[i][2]<<'\n';
	sz0 = sz(crd[0]);
	sz1 = sz(crd[1]);
	sz2 = sz(crd[2]);
	seg bmx(sz1),cmx(sz2);
	//cout<<"points"<<'\n';
	for(int i=0;i<n;i++){
		pts1[i][0] = pts2[i][0] = -2e9;
		pts1[i][1] = a[i][1]; //i has bigger b
		pts2[i][2] = a[i][2]; //i has bigger c
		int s1 = lower_bound(all(crd[1]),a[i][1]) - crd[1].begin();
		int s2 = lower_bound(all(crd[2]),a[i][2]) - crd[2].begin();
		if(s1>0)pts1[i][2] = bmx.query(1,0,s1-1,0,sz1-1); //want the max of c among smaller bs
		if(s2>0)pts2[i][1] = cmx.query(1,0,s2-1,0,sz2-1); //want the max of b among smaller cs
		if(pts1[i][2] > a[i][2])pts1[i][0] = pts1[i][1] + pts1[i][2]; 
		if(pts2[i][1] > a[i][1])pts2[i][0] = pts2[i][1] + pts2[i][2];
		bmx.upd(1,s1,0,sz1-1,a[i][2]);
		cmx.upd(1,s2,0,sz2-1,a[i][1]);
		
		//if(pts1[i][0] != -2e9)pts1[i][2] = lower_bound(all(crd[2]),pts1[i][2]) - crd[2].begin();
		//if(pts2[i][0] != -2e9)pts2[i][2] = lower_bound(all(crd[2]),pts2[i][2]) - crd[2].begin();
		//this is correct
	}
	for(int i=0;i<n;){
		int k = i;
		while(k+1<n && a[k][0] == a[k+1][0])k++;
		for(int x=i;x<=k;x++){
			for(int j=0;j<x;j++){
				if(a[x][0] == a[j][0])break;
				if(pts1[j][1] > a[x][1] && pts1[j][2] >a[x][2])ans = max(ans,a[x][0] + pts1[j][0]);
				if(pts2[j][1] > a[x][1] && pts2[j][2] >a[x][2])ans = max(ans,a[x][0] + pts2[j][0]);
			}
		}
		i = k+1;
	}
	for(int i=0;i<n;i++){
		a[i][0] = lower_bound(all(crd[0]),a[i][0]) - crd[0].begin();
		a[i][1] = lower_bound(all(crd[1]),a[i][1]) - crd[1].begin();
		a[i][2] = lower_bound(all(crd[2]),a[i][2]) - crd[2].begin();
		pts[a[i][0]].pb(i);
	}
	//amx = seg(sz2);
	//solve(0,sz1-1);
	cout<<ans;
	
	
	
}

• Subtask 1: 8 / 8
• Subtask 2: 29 / 29
• Subtask 3: 0 / 9
• Subtask 4: 0 / 9
• Subtask 5: 0 / 9
• Subtask 6: 0 / 9
• Subtask 7: 0 / 27