oj.uz

답안 #61863

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
61863 2018-07-27T01:17:35 Z Benq 괄호 문자열 (CEOI16_match) C++11
0 / 100
 3 ms 340 KB 
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

string x;
char ans[MX];

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> x;
    vi v;
    F0R(i,sz(x)) {
        if (sz(v) && x[v.back()] == x[i]) {
            ans[v.back()] = '(';
            ans[i] = ')';
            v.pop_back();
        } else v.pb(i);
    }
    if (sz(v) == 0) {
        F0R(i,sz(x)) cout << ans[i];
        exit(0);
    }
    cout << -1;
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

Subtask #1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 3 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 3 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 63.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 3 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -