이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "shortcut.h"
#include <bits/stdc++.h>
using namespace std;
long long find_shortcut(int n, vector<int>l, vector<int>d, int c) {
long long ans = LLONG_MAX;
vector<long long>x(n);
x[0] = 0;
for(int i = 1 ; i < n ; i++)
x[i] = x[i-1] + l[i-1];
for(int i = 0 ; i < n ; i++) {
for(int j = i+1 ; j < n ; j++) {
long long mx = 0;
for(int ii = 0 ; ii < n ; ii++) {
for(int jj = ii+1 ; jj < n ; jj++) {
if(jj <= i)
mx = max(mx, x[jj]-x[ii]+d[jj]+d[ii]); // +d
else if(ii >= j)
mx = max(mx, x[jj]-x[ii]+d[jj]+d[ii]);
else if(ii >= i && ii <= j && jj >= j)
mx = max(mx, min(x[jj]-x[ii]+d[ii]+d[jj], x[jj]-x[j]+c+x[ii]-x[i]+d[ii]+d[jj]));
else if(ii <= i && jj >= i && jj <= j)
mx = max(mx, min(x[jj]-x[ii]+d[ii]+d[jj], x[i]-x[ii]+c+x[j]-x[jj]+d[ii]+d[jj]));
else if(ii <= i && jj >= j)
mx = max(mx, min(x[jj]-x[ii]+d[ii]+d[jj], x[jj]-x[j]+c+x[i]-x[ii]+d[ii]+d[jj]));
else
mx = max(mx, min(x[jj]-x[ii]+d[ii]+d[jj], x[j]-x[jj]+c+x[ii]-x[i]+d[ii]+d[jj]));
}
}
//cout << i << ' ' << j << ' ' << mx << '\n';
ans = min(ans, mx);
}
}
return ans;
}
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