제출 #614128

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
614128		amunduzbaev	Two Antennas (JOI19_antennas)	C++17	100 / 100	754 ms	55608 KiB

antennas

#include "bits/stdc++.h"
using namespace std;
 
#define ar array
typedef long long ll;
#define int ll
#define sow cerr<<"here"<<endl;

const int N = 2e5 + 5;
const int inf = 2e9;
struct ST{
	int tree[N << 2], mx[N << 2];
	int cost[N << 2];
	
	void init(){
		memset(tree, 1, sizeof tree);
		memset(cost, -1, sizeof cost);
		memset(mx, 0, sizeof mx);
	}
	
	void push(int x, int lx, int rx){
		if(lx == rx) return;
		mx[x << 1] = max(mx[x << 1], mx[x]);
		mx[x << 1 | 1] = max(mx[x << 1 | 1], mx[x]);
		cost[x << 1] = max(cost[x << 1], mx[x << 1] - tree[x << 1]);
		cost[x << 1 | 1] = max(cost[x << 1 | 1], mx[x << 1 | 1] - tree[x << 1 | 1]);
		mx[x] = 0;
	}
	
	void set(int i, int v, int lx = 0, int rx = N, int x = 1){
		if(lx == rx){
			tree[x] = v, mx[x] = 0;
			return;
		} int m = (lx + rx) >> 1;
		push(x, lx, rx);
		if(i <= m) set(i, v, lx, m, x << 1);
		else set(i, v, m + 1, rx, x << 1 | 1);
		tree[x] = min(tree[x << 1], tree[x << 1 | 1]);
		cost[x] = max(cost[x << 1], cost[x << 1 | 1]);
	}
		
	void add(int l, int r, int v, int lx = 0, int rx = N, int x = 1){
		if(lx > r || rx < l) return;
		if(lx >= l && rx <= r){
			mx[x] = max(mx[x], v);
			cost[x] = max(cost[x], mx[x] - tree[x]);
			return;
		} int m = (lx + rx) >> 1;
		push(x, lx, rx);
		add(l, r, v, lx, m, x << 1);
		add(l, r, v, m + 1, rx, x << 1 | 1);
		cost[x] = max(cost[x << 1], cost[x << 1 | 1]);
	}
	
	int get(int l, int r, int lx = 0, int rx = N, int x = 1){
		if(lx > r || rx < l) return -inf;
		if(lx >= l && rx <= r){
			//~ cout<<lx<<" "<<rx<<" "<<cost[x]<<endl;
			return cost[x];
		} int m = (lx + rx) >> 1;
		push(x, lx, rx);
		return max(get(l, r, lx, m, x << 1), get(l, r, m + 1, rx, x << 1 | 1));
	}
}tree; 

int h[N], a[N], b[N];
int l[N], r[N], res[N];
vector<ar<int, 2>> Q[N];
int n, q;
int mx[N], mn[N];
int cost[N];

/*

5
10 2 4
1 1 1
2 1 3
1 1 1
100 1 1
1
1 2

*/

void solve(){
	tree.init();
	vector<int> p(q); iota(p.begin(), p.end(), 0);
	sort(p.begin(), p.end(), [&](int i, int j){
		return r[i] < r[j];
	});
	
	memset(cost, -1, sizeof cost);
	//~ auto set = [&](int i, int v){
		//~ mn[i] = v, mx[i] = 0;
	//~ };
	for(int i=0;i<n;i++){
		tree.set(i, inf);
		//~ set(i, inf);
	}
	//~ auto add = [&](int l, int r, int v){
		//~ for(int i=l;i<=r;i++){
			//~ mx[i] = max(mx[i], v);
			//~ cost[i] = max(cost[i], mx[i] - mn[i]);
		//~ }
	//~ };
	//~ auto get = [&](int l, int r){
		//~ int res = 0;
		//~ for(int i=l;i<=r;i++){
			//~ res = max(res, cost[i]);
		//~ }
		//~ return res;
	//~ };
	
	int j = 0;
	for(int i=0;i<n;i++){
		for(auto [j, t] : Q[i]){
			if(t){
				tree.set(j, h[j]);
			} else {
				tree.set(j, inf);
			}
		} Q[i].clear();
		
		int L = max(i - b[i], 0ll), R = i - a[i];
		if(L <= R){
			tree.add(L, R, h[i]);
		}
		Q[min(i + a[i], n)].push_back({i, 1});
		Q[min(i + b[i] + 1, n)].push_back({i, 0});
		
		while(j < q && r[p[j]] == i){
			res[p[j]] = max(res[p[j]], tree.get(l[p[j]], r[p[j]]));
			j++;
		}
	} Q[n].clear();
}

signed main(){
	ios::sync_with_stdio(0); cin.tie(0);
	
	//~ freopen("in.txt", "r", stdin);
	//~ freopen("out.txt", "r", stdin);
	cin >> n;
	for(int i=0;i<n;i++) cin >> h[i] >> a[i] >> b[i];
	cin >> q;
	for(int i=0;i<q;i++){
		cin >> l[i] >> r[i];
		l[i]--, r[i]--;
	}
	memset(res, -1, sizeof res);
	solve();
	reverse(h, h + n);
	reverse(a, a + n);
	reverse(b, b + n);
	for(int i=0;i<q;i++) l[i] = n - l[i] - 1, r[i] = n - r[i] - 1, swap(l[i], r[i]);
	solve();
	for(int i=0;i<q;i++) cout<<res[i]<<"\n";
}

• Subtask 1: 2 / 2
• Subtask 2: 11 / 11
• Subtask 3: 22 / 22
• Subtask 4: 65 / 65