Submission #614114

#TimeUsernameProblemLanguageResultExecution timeMemory
614114chirathnirodhaMeetings (IOI18_meetings)C++17
19 / 100
584 ms4364 KiB
#include "meetings.h" #include<bits/stdc++.h> using namespace std; #define PB push_back #define MP make_pair #define F first #define S second #define P push typedef long long ll; int n,q; vector<ll> hei; vector<ll> SUB_1_2(vector<int> L,vector<int> R) { vector<ll> C; for(int h=0;h<q;h++){ ll ans=INT64_MAX; ll vall[n],valr[n]; vector<int> v; ll cur=hei[L[h]];vall[L[h]]=cur; v.PB(L[h]); for(int i=L[h]+1;i<=R[h];i++){ while(!v.empty()){ int last=v.back(); if(hei[last]>=hei[i])break; v.pop_back(); if(v.empty())cur+=(hei[i]-hei[last])*(last-L[h]+1); else cur+=(hei[i]-hei[last])*(last-v.back()); } v.PB(i);cur+=hei[i]; vall[i]=cur; } v.clear(); cur=hei[R[h]];valr[R[h]]=cur; v.PB(R[h]); for(int i=R[h]-1;i>=L[h];i--){ while(!v.empty()){ int last=v.back(); if(hei[last]>=hei[i])break; v.pop_back(); if(v.empty())cur+=(hei[i]-hei[last])*(R[h]-last+1); else cur+=(hei[i]-hei[last])*(v.back()-last); } v.PB(i);cur+=hei[i]; valr[i]=cur; } for(int i=L[h];i<=R[h];i++){ ans=min(ans,vall[i]+valr[i]-hei[i]); } C.PB(ans); } return C; } int seg[400010]; void update(int a,int b,int c,int x,int y){ if(seg[c]==b-a+1)return; if(a==b){ seg[c]=max(seg[c],y-x+1); return; } int m=(a+b)/2; if(y<=m)update(a,m,2*c,x,y); else if(x>m)update(m+1,b,2*c+1,x,y); else { update(a,m,2*c,x,m); update(m+1,b,2*c+1,m+1,y); } return; } int findseg(int a,int b,int c,int x,int y){ if(a==x && b==y)return seg[c]; int m=(a+b)/2; if(y<=m)return findseg(a,m,2*c,x,y); else if(x>m)return findseg(m+1,b,2*c+1,x,y); else return max(findseg(a,m,2*c,x,m),findseg(m+1,b,2*c+1,m+1,y)); } vector<ll> SUB_3(vector<int> L,vector<int> R) { memset(seg,0,sizeof(seg)); int cur=-1; for(int i=0;i<n;i++){ if(hei[i]==2){ if(cur+1<=i-1)update(0,n-1,1,cur+1,i-1); cur=i; } } if(cur+1<=n-1)update(0,n-1,1,cur+1,n-1); vector<ll> C; for(int i=0;i<q;i++){ int ones=findseg(0,n-1,1,L[i],R[i]); ll val=ones+2*(R[i]-L[i]+1-ones); C.PB(val); } return C; } vector<ll> minimum_costs(vector<int> H, vector<int> L,vector<int> R) { n=H.size();q=L.size(); for(int i=0;i<n;i++)hei.PB((ll)H[i]); if(n<=5000 && q<=5000)return SUB_1_2(L,R); else return SUB_3(L,R); }
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