Submission #613816

#TimeUsernameProblemLanguageResultExecution timeMemory
613816yuto1115Newspapers (CEOI21_newspapers)C++17
12 / 100
8 ms12648 KiB
#include <bits/stdc++.h> #define rep(i, n) for(ll i = 0; i < ll(n); ++i) #define rep2(i, s, n) for(ll i = ll(s); i < ll(n); ++i) #define rrep(i, n) for(ll i = ll(n) - 1; i >= 0; --i) #define rrep2(i, n, t) for(ll i = ll(n) - 1; i >= ll(t); --i) #define pb push_back #define eb emplace_back #define all(a) a.begin(), a.end() #define SZ(a) int(a.size()) using namespace std; using ll = long long; using P = pair<int, int>; using vi = vector<int>; using vvi = vector<vi>; using vl = vector<ll>; using vvl = vector<vl>; using vp = vector<P>; using vvp = vector<vp>; using vb = vector<bool>; using vvb = vector<vb>; using vs = vector<string>; const int inf = 1001001001; const ll linf = 1001001001001001001; template<class T> bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template<class T> bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr), cout.tie(nullptr); int n, m; cin >> n >> m; if (n == 1) { cout << "YES\n1\n1\n" << endl; return 0; } vvi G(n); rep(i, m) { int u, v; cin >> u >> v; --u, --v; G[u].pb(v); G[v].pb(u); } assert(n <= 20); vi d(1 << n, inf); vp pre(1 << n); queue<int> q; d[(1 << n) - 1] = 0; q.push((1 << n) - 1); while (not q.empty()) { int now = q.front(); q.pop(); int nx = 0; rep(i, n) { for (int j: G[i]) { if (now >> j & 1) nx |= 1 << i; } } rep(i, n) { if (~nx >> i & 1) continue; nx -= 1 << i; if (chmin(d[nx], d[now] + 1)) { q.push(nx); pre[nx] = {now, i}; } nx += 1 << i; } } if (d[0] == inf) { cout << "NO" << endl; return 0; } cout << "YES" << endl; vi ans; int now = 0; while (now < (1 << n) - 1) { ans.pb(pre[now].second + 1); now = pre[now].first; } reverse(all(ans)); cout << SZ(ans) << endl; rep(i, SZ(ans)) cout << ans[i] << (i < SZ(ans) - 1 ? ' ' : '\n'); // if (m > n - 1) { // cout << "NO" << endl; // return 0; // } //// vb in(n); //// rep(i, n) in[i] = SZ(G[i]) > 1; //// rep(i, n) { //// if (!in[i]) continue; //// int cnt = 0; //// for (int j: G[i]) if (in[j]) ++cnt; //// if (cnt > 3) { //// cout << "NO" << endl; //// return 0; //// } //// } // cout << "YES" << endl; // cout << "1\n1\n"; }
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