이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "prize.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define eb emplace_back
#define pb push_back
#define ft first
#define sd second
#define pi pair<int, int>
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define dbg(...) dbg_out(__VA_ARGS__)
using ll = long long;
using ld = long double;
using namespace std;
using namespace __gnu_pbds;
//Constants
const ll INF = 5 * 1e18;
const int IINF = 2 * 1e9;
const ll MOD = 1e9 + 7;
// const ll MOD = 998244353;
const ll dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};
const ld PI = 3.14159265359;
//Templates
template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) {return os << '(' << p.first << ", " << p.second << ')';}
template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) {os << '['; string sep; for (const T &x : v) os << sep << x, sep = ", "; return os << ']';}
void dbg_out() {cerr << endl;}
template<typename Head, typename... Tail> void dbg_out(Head H, Tail... T) { cerr << H << ' '; dbg_out(T...); }
template<typename T> void mins(T& x, T y) {x = min(x, y);}
template<typename T> void maxs(T& x, T y) {x = max(x, y);}
template<typename T> using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T> using omset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;
int find_best(int n) {
int mx = 0;
for (int i = 0; i < min(n, 600); i++) {
vector<int> res = ask(i);
int cur = res[0] + res[1];
if (cur == 0) return i;
maxs(mx, cur);
}
vector<pi> al;
function<void(int, int)> solve = [&](int left, int right) {
if (left > right) return;
int mi = (left + right) / 2;
vector<int> res;
int pleft = mi, pright = mi;
while (pleft >= left) {
res = ask(pleft);
if (res[0] + res[1] == mx) break;
al.pb({res[0] + res[1], pleft});
pleft--;
}
while (pright <= right) {
res = ask(pright);
if (res[0] + res[1] == mx) break;
al.pb({res[0] + res[1], pright});
pright++;
}
solve(left, pleft - 1);
solve(pright + 1, right);
};
solve(0, n - 1);
sort(all(al));
return al[0].sd;
}
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