Submission #611966

#	Time	Username	Problem	Language	Result	Execution time	Memory
611966		tranxuanbach	Poi (IOI09_poi)	C++17	0 / 100	279 ms	23768 KiB

poi

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

#define endl '\n'
#define fi first
#define se second
#define For(i, l, r) for (auto i = (l); i < (r); i++)
#define ForE(i, l, r) for (auto i = (l); i <= (r); i++)
#define FordE(i, l, r) for (auto i = (l); i >= (r); i--)
#define Fora(v, a) for (auto v: (a))
#define bend(a) (a).begin(), (a).end()
#define isz(a) ((signed)(a).size())

using ll = long long;
using ld = long double;
using pii = pair <int, int>;
using vi = vector <int>;
using vpii = vector <pii>;
using vvi = vector <vi>;

const int N = 2e3 + 5;

int n, m, k;
int a[N][N];

int b[N], c[N], d[N];

signed main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    // freopen("KEK.inp", "r", stdin);
    // freopen("KEK.out", "w", stdout);
    cin >> n >> m >> k;
    ForE(i, 1, n){
        ForE(j, 1, m){
            cin >> a[i][j];
        }
    }
    ForE(j, 1, m){
        ForE(i, 1, n){
            if (a[i][j] == 0){
                b[j]++;
            }
        }
        ForE(i, 1, n){
            if (a[i][j] == 1){
                c[i] += b[j];
                d[i]++;
            }
        }
    }
    cout << c[k] << ' ';
    vi e(n); iota(bend(e), 1);
    sort(bend(e), [&](int i, int j){
        if (c[i] != c[j]){
            return c[i] < c[j];
        }
        if (d[i] != d[j]){
            return d[i] < d[j];
        }
        return i < j;
    });
    ForE(i, 1, n){
        if (e[i - 1] == k){
            cout << i << endl;
            break;
        }
    }
}

/*
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INPUT:                                            |
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OUTPUT:                                           |
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*/

• Subtask 1: 0 / 100